Answer:
Step-by-step explanation:
look at 2=x-y=2
move this term to the left (2)
it becomes 2=x-y+2=0
and thats your results
Examples: x^2-2x=-1, 3x-x-x+a-a=5, (x^2-1)/(x+1), 2x-(x+x)
She would have to work at least 12 hours.
At Chili’s, she would be paid 11.75x + 33 per week, with x being the number of hours she worked.
At the Cheesecake Factory, Giselle would be paid 14.50x per week, with x being how many hours she worked.
We want to know how many hours Gisele would have to work for her pay at the Cheesecake Factory to be more than her pay at Chili’s
The inequality 11.75x + 33 < 14.50x is what has to be set up to solve the problem. At how many hours will the pay on the left be less than the pay on the right?
11.75x + 33 < 14.50x
33 < 2.75x
12 < x
So Giselle has to work greater 12 hours a week for her to make more money at the Cheesecake Factory.
Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:
and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders: 
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: 
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
The volume of a sphere, V = (4/3)(PI)(R^3)
Let k = (4/3)(PI)
Therefore, V = k (R^3)
Let R’ = new radius = 2R
V’ =k (R’^3)
= k (2R)^3
= 8 k R^3
= 8 V
The volume would be eight time the original volume.
Answer:
46.6
Step-by-step explanation:
