What is the start velocity of a javelin accelerated at 3.75 m/s2 for 2 seconds, and reaching 9375 m/s?
1 answer:
Answer:
Step-by-step explanation:
u = ?
a = 3.75m/s^2
t = 2 s
v = 9375m/s
a = v-u/t
3.75 = 9375 - u / 2
3.75 × 2 = 9375 - u
7.5 = 9375 - u
u = 9375 - 7.5
=<em> 9367.5 m/s</em>
<em>Hope this helps</em>
<em>plz mark as brainliest!!!!!!!</em>
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Answer:
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Step-by-step explanation:
Work will be shown below:
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c>27
Answer:
44
Step-by-step explanation:
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