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sp2606 [1]
2 years ago
7

What is the number of liters in 90 gallons

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
6 0
The answer is 340.687 liters

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What is 8,888,888,823,456 divided by 9
Digiron [165]

Answer: 987,654,314,000

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What group of numbers does -2 belong to?
Marizza181 [45]
Answer: Integers and Rational Numbers

Explanation: -2 is an integer because integers include positive an negative numbers. It would not be a whole number or a Naural number because both of those sets only include positive numbers. Here’s a better explanation:

Natural numbers: Natural Numbers are like (1,2,3....). They only include positive numbers. Therefore, -2 does not belong in this category.

Whole Numbers: Whole Numbers are like (0,1,2,3....). They include all the natural numbers with 0. Therefore, -2 does not belong in this set.

Integers: Integers include both positive and negative numbers. They are like (-3,-2,-1,0,1,2,3....). Since they both have positive and negative numbers, -2 would belong in this set.

Rational Numbers: Rational Numbers include ALL the sets that were described. (Natural, Whole, Integer). Since this set also includes positive and negative numbers, -2 would belong in this set.

So, -2 belongs in Integers and Rational Numbers

Hope this helps!
3 0
3 years ago
Let B=[-1 3 6 -3].Find-4B.
vaieri [72.5K]

The product of a scalar and a matrix is found by multiplying each element of the matrix by the scalar. Multiply each element by -4.

... [4 -12 -24 12]

4 0
3 years ago
Help! Please. I don’t know what to do. I got this wrong. Thanks.
strojnjashka [21]

Answer: I believe the answer would be 1/9 ?

7 0
2 years ago
Question 6
inna [77]

Answer:

add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract

complex numbers by adding their real and imaginary parts:-

(a + bi)+(c + di)=(a + c)+(b + d)i,

(a + bi) − (c + di)=(a − c)+(b − d)i.

We can multiply complex numbers by expanding the brackets in the usual fashion and using i

2 = −1,

(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,

and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So

a + bi

c + di = a + bi

c + di ×

c − di

c − di =

µac + bd

c2 + d2

¶

+

µbc − ad

c2 + d2

¶

i.

The number c−di which we just used, as relating to c+di, has a spec

7 0
2 years ago
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