y=kx
soda water=k orange juice
2=2k
k=1
18=1 × orange juice
orange juice=18/1
orange juice=18 cups
The second one. Hope this helps:)
6,025, 305< 6,026,305< 6,027,305.
Answer: 
Step-by-step explanation:
<u>Given expression</u>
![\large\boxed{\frac{12[30 - (9+4^2)]}{|10|-|-6| } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cfrac%7B12%5B30%20-%20%289%2B4%5E2%29%5D%7D%7B%7C10%7C-%7C-6%7C%20%7D%20%7D)
<u>Simplify the exponents</u>
![\large\boxed{=\frac{12[30 - (9+16)]}{|10|-|-6| } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D%5Cfrac%7B12%5B30%20-%20%289%2B16%29%5D%7D%7B%7C10%7C-%7C-6%7C%20%7D%20%7D)
Simplify values in the parenthesis
![\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D%5Cfrac%7B12%5B30%20-%2025%5D%7D%7B%7C10%7C-%7C-6%7C%20%7D%20%7D)
![\large\boxed{=\frac{12[5]}{|10|-|-6| } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D%5Cfrac%7B12%5B5%5D%7D%7B%7C10%7C-%7C-6%7C%20%7D%20%7D)
<u>Simplify absolute values (all positive)</u>
![\large\boxed{=\frac{12[5]}{10-6 } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D%5Cfrac%7B12%5B5%5D%7D%7B10-6%20%7D%20%7D)
![\large\boxed{=\frac{12[5]}{4 } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D%5Cfrac%7B12%5B5%5D%7D%7B4%20%7D%20%7D)
<u>Simplify by division</u>
![\large\boxed{=3~[5]}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%3D3~%5B5%5D%7D)
<u>Simplify by multiplication</u>
Hope this helps!! :)
Please let me know if you have any questions
Answer:
Step-by-step explanation:
(-4,-8)...x = -4 and y = -8
slope = 3/2
in y = mx + b form, the m is ur slope
now sub ur info into y = mx + b......we need to find b, the y intercept
y = mx + b
-8 = 3/2(-4) + b
-8 = -6 + b
-8 + 6 = b
-2 = b
so ur equation is : y = 3/2x - 2.....but u need it in another form
y = 3/2x - 2.....subtract 3/2x from both sides
-3/2x + y = -2 ....then u can multiply by -2 and get 3x - 2y = 4....just in case u dont want fractions
Answer:
13/12
Step-by-step explanation:
common multiple is 12 the times the numerator of each fraction to get an equivalent fraction, then add them together
