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Leona [35]
3 years ago
10

There are small, medium, and large shirts in blue, white, or gray. How many different possible outcomes are there?

Mathematics
2 answers:
stira [4]3 years ago
8 0

3 different sizes.

3 different colors.

Total outcomes: number of sizes x number of colors.

3 x 3 = 9

There are 9 total outcomes.

andreyandreev [35.5K]3 years ago
6 0

GIVEN:

  • No. of colors = 3
  • No. of sixes = 3

ANSWER:

Total possible outcomes = 3 × 3

  • 9

So, <u>Correct choice</u> - [A] 9.

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Butoxors [25]

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7 0
3 years ago
7)<br> Which could be solved for x?<br> 2x+ 2<br> B)<br> 3(x+2)<br> 3x+4<br> 3x=12<br> D
dem82 [27]

Answer:

3x=12

Step-by-step explanation:

x=12/3 => x=4

8 0
3 years ago
PLEASE HELP REALLY QUICK I WILL REWARD BRAINLIEST PUT FULL EXPLANATION AND ANSWER TO THE QUESTION BELOW!!!!!!!!
Mariulka [41]

Answer:

x = 27

Step-by-step explanation:

36 + 90 + 2x = 180 \\ 126 + 2x = 180 \\ 2x = 180 - 126 \\ 2x = 54 \\  \\ x =  \frac{54}{2}  \\  \\ x = 27

I hope I helped you^_^

4 0
2 years ago
If x - y =5, x + y =1, then x^2 - y^2= ??<br><br>+explanation please and thanks​
Sveta_85 [38]
<h3>Answer:  5</h3>

=================================

Explanation:

Apply the difference of squares rule

x^2 - y^2 = (x-y)(x+y)

x^2 - y^2 = (5)(1)

x^2 - y^2 = 5

----------

Alternatively, you can solve the system

\begin{cases}x-y=5\\x+y = 1\end{cases}

for x and y to get (x,y) = (3,-2).

Then compute x^2-y^2 = 3^2-(-2)^2 = 9-4 = 5

8 0
3 years ago
A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

7 0
4 years ago
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