3 years ago

3y + 5 > 23 Please Solve And Show your work

1 answer:

6 0

3y + 5 > 23
Solve as if it is an equation
3y + 5 > 23
subtract 5 from both sides
3y > 18
divide both sides by 3
y > 6

Hope this helps

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Answers:

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Work shown for part 1

$f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\$

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Work shown for part 2

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\$

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Step-by-step explanation:

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the measure of angle 5 is 15 I believe
do you have a picture of the problem to see if I'm correct?

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