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juin [17]
3 years ago
14

McCoy Brothers manufactures and sells two products, A and Z in the ratio of 4:2. Product A sells for $75; Z sells for $95. Varia

ble costs for product A are $35; for Z $40. Fixed costs are $418,500. Compute the number of units of Product Z McCoy must sell to break even.
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

3100 units of Product Z

Step-by-step explanation:

The ratio is 4 is to 2, that means:

4 + 2 = 6 parts total

Now,

We have to cover the fixed cost of 418,500 from profits, that is SP - VC

Where SP is Selling Price and VC is Variable Cost

Product A:

SP = 75

VC = 35

Profit = 40

Product B:

SP = 95

VC = 40

Profit = 55

So, we can sell "4x" of product A and "2x" of product B, and create the equation:

4x(40) + 2x(55) = 418,500

Now, we solve for x:

4x(40) + 2x(55) = 418,500\\160x + 110x = 418,500\\270x=418500\\x=1550

The amount of Product Z was taken as "2x", so the quantity of Product Z would be:

2(1550) = <u>3100 units of Product Z</u>

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Serggg [28]
Because he has 4 pounds of apples left, you are to subtract that from the total pounds picked, which was a total of 55 pounds. So 55 with 4 taken away, or 55 - 4, equals 51. Since he had equally put 51 pounds into six bags, you are to then divide . 51 / 6 = 8.5. He had put 8.5 pounds worth of apples into each bag.
4 0
2 years ago
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Help meeee pleaseeeee
dsp73

3 = 379.25

4 = 1587.50

5 = 198.88

6 = 1217.50

7 = 1788.20

8 = 1408

9 = 205

10 = 1516

11 = 2034

12 = 880

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7 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
2 years ago
In a group of 48 children there are three times as many boys as girls. how many girls are there
Leno4ka [110]
If x=girls,
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We know that all children are boys+girls, so x+3x, which is 4x and 4x is 48, so one x is 12.

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5 0
3 years ago
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If E F = 7 , A C = 16 , and A F = 9
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Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
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