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Sidana [21]
3 years ago
12

A.20° b.15° c.30° d.60° e. 90°

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

The answer is D. 60

Brainliest please I need to get to the next rank

Step-by-step explanation:

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Grant decided to buy some cookies from tiff
Alja [10]

Answer:

3+.50d=

Step-by-step explanation:

3 represents $3.00

.50 represents $0.50 for each mile

d represents the total cost

6 0
2 years ago
!!Find the area of the shaded region!! (worth 20 points)
Leona [35]

Answer:

shaded area = 8.7 ft²

Step-by-step explanation:

area of circle = πr² = (3.14)(4²) = 50.24 ft²

apothem of hexagon = (sin 60° x 4) = 3.464

area of hexagon = 1/2(3.464)(6)(4) = 41.56 ft²

50.24 - 41.56 = 8.68 ft²

6 0
3 years ago
TIMED PLEASE HURRY HELP WITH 2 EASY QUESTIONS
Alex_Xolod [135]
<h2>                         Question # 1</h2><h2>Which statements are true?</h2><h2 /><h3><u>Analyzing and solving the first statement:</u></h3>
  • 4g^2-g=g^2\left(4-g\right)

Solving the expression

4g^2-g

\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c

g^2=gg

So,

4gg-g

\mathrm{Factor\:out\:common\:term\:}g

g\left(4g-1\right)

So,

4g^2-g:\quad g\left(4g-1\right)

Therefore, the statement 4g^2-g=g^2\left(4-g\right) is NOT CORRECT.

<h3><u>Analyzing and solving the second statement:</u></h3>
  • 35g^5-25g^2=\:5g^2\left(7g^3-5\right)

Solving the expression

35g^5-25g^2

\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c

g^5=g^3g^2

So,

35g^3g^2-25g^2

\mathrm{Rewrite\:}25\mathrm{\:as\:}5\cdot \:5

\mathrm{Rewrite\:}35\mathrm{\:as\:}5\cdot \:7

5\cdot \:7g^3g^2-5\cdot \:5g^2

\mathrm{Factor\:out\:common\:term\:}5g^2

5g^2\left(7g^3-5\right)

So,

35g^5-25g^2=\:5g^2\left(7g^3-5\right)

Therefore, the statement 35g^5-25g^2=\:5g^2\left(7g^3-5\right) is CORRECT.

<h3><u>Analyzing and solving the third statement:</u></h3>
  • 24g^4+18g^2=\:6g^2\left(4g^2+3g\right)
<h3 />

Solving the expression

<h3>24g^4+18g^2</h3><h3>24g^2g^2+18g^2</h3><h3>\mathrm{Rewrite\:}18\mathrm{\:as\:}6\cdot \:3</h3><h3>\mathrm{Rewrite\:}24\mathrm{\:as\:}6\cdot \:4</h3><h3>6\cdot \:4g^2g^2+6\cdot \:3g^2</h3><h3>\mathrm{Factor\:out\:common\:term\:}6g^2</h3><h3>6g^2\left(4g^2+3\right)</h3>

So,

<h3>24g^4+18g^2=6g^2\left(4g^2+3\right)</h3>

Therefore, the statement 24g^4+18g^2=\:6g^2\left(4g^2+3g\right)  is CORRECT.

<h3><u>Analyzing and solving the fourth statement:</u></h3>
  • 9g^3+12=\:3\left(3g^3+4\right)

Solving the expression

9g^3+12

\mathrm{Rewrite\:}12\mathrm{\:as\:}3\cdot \:4

\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3

3\cdot \:3g^3+3\cdot \:4

\mathrm{Factor\:out\:common\:term\:}3

3\left(3g^3+4\right)

So,

9g^3+12=\:3\left(3g^3+4\right)

Therefore, the statement 9g^3+12=\:3\left(3g^3+4\right) is CORRECT.

<h2>                         Question # 2</h2><h2>Which expressions are completely factored?</h2>

<u>Solving first expression</u>

Considering the expression

  • 30a^6-24a^2

30a^6-24a^2

30a^4a^2-24a^2

\mathrm{Rewrite\:}24\mathrm{\:as\:}6\cdot \:4

\mathrm{Rewrite\:}30\mathrm{\:as\:}6\cdot \:5

6\cdot \:5a^4a^2-6\cdot \:4a^2

\mathrm{Factor\:out\:common\:term\:}3a^2

3a^2\left(10a^4-8\right)

Thus, the expression 30a^6-24a^2=3a^2\left(10a^4-8\right)\: is completely factored.

<u>Solving second expression</u>

Considering the expression

  • 12a^3-8a

12a^3-8a

\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c

a^3=a^2a

So,

12a^2a-8a

\mathrm{Rewrite\:}8\mathrm{\:as\:}4\cdot \:2

\mathrm{Rewrite\:}12\mathrm{\:as\:}4\cdot \:3

4\cdot \:3a^2a-4\cdot \:2a

\mathrm{Factor\:out\:common\:term\:}4

4\left(3a^3-2a\right)

Thus, the expression 12a^3-8a=\:4\left(3a^3-2a\right) is completely factored.

<u>Solving third expression</u>

  • 16a^5-20a^3\:\:\:\:\:\:\:\:\:\:\:\:

16a^5-20a^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c

a^5=a^2a^3

So,

16a^2a^3-20a^3

\mathrm{Rewrite\:}20\mathrm{\:as\:}4\cdot \:5

\mathrm{Rewrite\:}16\mathrm{\:as\:}4\cdot \:4

4\cdot \:4a^2a^3-4\cdot \:5a^3

\mathrm{Factor\:out\:common\:term\:}4a^3

4a^3\left(4a^2-5\right)

Thus, the expression 16a^5-20a^3\:=4a^3\left(4a^2-5\right) is completely factored.

<u>Solving fourth expression</u>

  • 24a^4+18

24a^4+18

\mathrm{Rewrite\:}18\mathrm{\:as\:}6\cdot \:3

\mathrm{Rewrite\:}24\mathrm{\:as\:}6\cdot \:4

6\cdot \:4a^4+6\cdot \:3

\mathrm{Factor\:out\:common\:term\:}6

6\left(4a^4+3\right)

Thus, the expression 24a^4+18=6\left(4a^4+3\right) is completely factored.

Keywords: expression, factoring

Learn more about expression factoring from brainly.com/question/14051207

#learnwithBrainly

8 0
3 years ago
30. While making a dessert, Jane used
antiseptic1488 [7]

Answer:

Jane used 2/5 of a scoop more of brown sugar than she did with white sugar.

Step-by-step explanation:

If you want to find how much more something is from something else, you subtract. So, subtract 9/10-1/2. If you want to subtract, they should both have the same denominator. So, 9/10-1/2 is the same as 9/10-5/10. 9/10-5/10 is equal to 4/10 which is simplified to 2/5.

4 0
3 years ago
Please help me find DOMAIN/RANGE and the EQATION
mrs_skeptik [129]

Answer:

Domain of the function → (-6, ∞)

Range of the function → (-∞, ∞)

Step-by-step explanation:

Domain of a function is the set of x-values of the function.

Similarly, Range of the function is the set of y-values.

From the graph attached,

Domain of the function → (-6, ∞)

x-values of the function starts from x = -6 (excluding x = -5) and tends to the positive infinity.

Range of the function → (-∞, ∞)

y-values starts from negative infinity and tends to positive infinity.

7 0
3 years ago
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