We have to break each degree in terms of 90
A) 
Which is in third quadrant, therefore sine is negative hence

B) 
Which is in third quadrant, therefore cosine is negative hence

C) 
Which is in third quadrant, therefore tangent is positive hence

D) 
Which is in third quadrant, therefore cosec is negative hence
not defined
E)
Which is in third quadrant, therefore secant is negative hence

F) 
Which is in third quadrant, therefore tangent is positive hence
not defined
Hence only
and
have value -1
Hope this will help
Mark can make 303,030 birthday cakes.
Answer:
Step-by-step explanation:
3x - 3y = 3(x-y)
-1, 0, 1/2, 6, 9 hope that helps