Dr. Roberts examined the cells of four different organisms for the presence of various cellular structures. His observations are
1 answer:
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Answer:
c. Aa Bb
Explanation:
The parents were pure breeding with genotypes AAbb and aaBB. A cross between AAbb and aaBB would produce AaBb genotypes in F1 progeny. Two F1 strains would be crossed to produce F2 progeny. The F2 progeny would have the genotype ratio= 1:2:1:2:4:2:1:2:1.
Out of all the obtained genotypes in the F2 generation, the proportion of "AaBb" genotype was 4/16. Therefore, "4" in the given ratio represents the genotype "AaBb".
