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2 years ago

40% of what number is 14

Mathematics

1 answer:

Virty [35]2 years ago

6 0

0.4x = 14
x = 14/0.4 = 35

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PLZ Help!!!<br> Look at the pic.

stealth61 [152]

435 being the constant means that is what they started with

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8 0

2 years ago

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Which of the following are solutions to the equation below?

34kurt

Answer:

B. 4

Step-by-step explanation:

Rearrange the equation so that is in the form (ax² + bx + c = 0).

6x² - 3x + 36 = 5x² + 10x

x² - 3x + 36 = 10x

x² - 13x + 36 = 0

Now, factor the equation and solve for x.

x² - 13x + 36 = 0

(x - 4)(x - 9) = 0

x - 4 = 0

x = 4

x - 9 = 0

x = 9

The solutions to the equation are 4 and 9. The correct answer choice is B.

6 0

2 years ago

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Those 2 questions I need help with . find sec θ and tanθ

Zielflug [23.3K]

STEP - BY - STEP EXPLANATION

What to find?

The the value of secθ.

Given:

(4, 3)

⇒(x, y) = (4, 3)

Step 1

Draw a sketch.

Step 2

Substitute the values into the trig. ratio formula below.

$tan\theta=\frac{opposite}{adjacent}$

From the sketch above, opposite = 3 and adjacent = 4

$tan\theta=\frac{3}{4}$

Step 3

Find the value of the hypotenuse side using Pythagoras theorem.

let h be the hypotenuse side.

$\begin{gathered} h^2=4^2+3^2 \\ \\ =16+9 \\ \\ =25 \\ \\ h=5 \end{gathered}$

Hence, hypotenuse = 5

Step 4

Substitute the values into the formula below:

$\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ \\ =\frac{4}{5} \end{gathered}$

But,

$sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}$

ANSWER

secθ= 5/4

tanθ=3/4

7 0

9 months ago

4/5 divided by 3 fraction.......

astra-53 [7]

Answer:

4/15

Step-by-step explanation:

$\frac{\frac{4}{5} }{3}=\frac{4}{5}(\frac{1}{3})=\frac{4}{15}$

5 0

2 years ago

Can anybody help me on this please I will be giving 15 points..

oksano4ka [1.4K]

Answer:

BC= $\sqrt{95}$

Angle A (or BAC)=54.31466...

Angle C (or ACB)=35.68533...

Step-by-step explanation:

$\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}$

$BC=\sqrt{12^2-7^2}$

$\sqrt{12^2-7^2}=\sqrt{95}$

$\frac{\sqrt{95}}{\sin \left(\angle \:BAC\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:BAC=54.31466$

$\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:ACB=35.68533$

4 0

3 years ago

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