Yesterday Cindy did of her homework. Today she did

1.5.3 Quiz: Literal Equations and Formulas

sweet-ann [11.9K]

Answer:

c = F-32; 68-32 = 36°C.

Step-by-step explanation:

the real conversation equation is f = 9/5 C + 32. but for the sake of this problem we are ignoring the coefficient.

so it's 36°C

3 0

2 years ago

In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen

Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type ni xi si

Graded 42 0.486 0.187

No-fines 42 0.359 0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

$Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}} + \frac{s_{2}^{2} }{n_{2}} } }$

$Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42} + \frac{0.02496 }{42} } }$

$Z = \frac{0.127 }{\sqrt{0.001468}}$

$Z = \frac{0.127 }{0.0377}$

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0

2 years ago

Find the missing angles 1-3

Marianna [84]

Answer:

ssdfggbbdbdbdbdbd d sbsbbsnsndnndnddhd

6 0

2 years ago

Find the surface area of the composite figure.

kakasveta [241]

Answer:

508.68 in^2

Step-by-step explanation:

The equation given: 2πr^2+2πrh

Givens: r = 3 in, h = 3*8 in = 24 in, π ≈ 3.14

Substitution: 2(3.14)3^2+2(3.14)3*24

Solution: 508.68

7 0

3 years ago

As of october 28th chris has only paid $50 of the $180 senior dues which is due by december 20th chris had to quit his job becau

valentina_108 [34]

Answer:

Step-by-step explanation:

I believe that the best advice in this scenario would be to fully pay off the senior dues and with the $48.56 that is left pay back as many lost books as possible. This would leave you owing $6.44 for lost books which you can ask Chris can ask his parents or work a small side gig to earn that money. The more important payment to make is the senior dues which have an actual due date unlike the lost books and can actually cause you trouble if not paid on time.

6 0

2 years ago