Hehsjrjsownsirieus disowned me because
Given:
area of square, A = 16 
error in area, dA = 0.03 cm^{2}
Step-by-Step Explanation:
Let 'a' be the side of the square
area of square, A =
(1)
A = 16 = 
Therefore, a = 4 cm
for max tolerable error in length 'da', differentiate eqn (1) w.r.t 'a':
dA = 2a da

da = 
da = 0.0375 cm