Ask question

Ask question

All categories

3 years ago

13

A garage door is 16 feet wide; the scale is 2 inches = 1 foot. How wide is the door on the scale drawing? Door = ________ inches

on the drawing.
I WILL REWARD BRAINLIEST

2 answers:

Galina-37 [17]3 years ago

4 0

Answer:

32

Step-by-step explanation:

yes

Shalnov [3]3 years ago

3 0

32

Hope this helps you

You might be interested in

Which models represent the sum? <br> 0.4 + 1.4

anygoal [31]

Answer:

I think it's the first one and the second one

7 0

3 years ago

Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 tim

Kamila [148]

Question:

Select the three expressions that are equivalent to $6^2$ :

a: $(\frac{6^9}{6^8})^2$

b: $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$

c: $\frac{6^4}{6^2}$

d: $\frac{6^5 * 6^7}{6^{10}}$

Answer:

a: $(\frac{6^9}{6^8})^2$

c: $\frac{6^4}{6^2}$

d: $\frac{6^5 * 6^7}{6^{10}}$

Step-by-step explanation:

Given

$6^2$ :

Required

Find equivalent expressions

<em>To solve this question; we'll simplify options a to do, one after the other</em>

a: $(\frac{6^9}{6^8})^2$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that;

$(\frac{6^9}{6^8})^2 = (6^{9-8})^2$

$(\frac{6^9}{6^8})^2 = (6^{1})^2$

From laws of indices;

${a^m}^n = a^{m*n} = a^{mn}$

This implies that

$(\frac{6^9}{6^8})^2 = (6^{1*2})$

$(\frac{6^9}{6^8})^2 = 6^{2}$

Hence, $(\frac{6^9}{6^8})^2$ is equivalent to $6^2$

b. $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$

From laws of indices;

$a^m * a^n = a^{m+n}$

This implies that

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}$

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{6}}{6^{3}}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{6-3}$

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{3}$

Hence; $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$ is not equivalent to $6^2$

c. $\frac{6^4}{6^2}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6^4}{6^2} = 6^{4-2}$

$\frac{6^4}{6^2} = 6^{2}$

Hence, $\frac{6^4}{6^2}$ is equivalent to $6^2$

d. $\frac{6^5 * 6^7}{6^{10}}$

From laws of indices;

$a^m * a^n = a^{m+n}$

This implies that

$\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}$

$\frac{6^5 * 6^7}{6^{10}} = 6^{2}$

Hence, $\frac{6^5 * 6^7}{6^{10}}$ is equivalent to $6^2$

3 0

3 years ago

Read 2 more answers

In triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). W

Vikki [24]

Answer:

The length of AD is 4 cm

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ ABC

- Point D lies on side AB ans point E lies on side BC

- Segment DE parallel to the side AC

- AB = 16 cm , AC = 20 cm , DE = 15 cm

* Lets solve the problem

- In Δ ABC

∵ DE // AC

∴ m∠BDE = m∠BAC ⇒ corresponding angles

∴ m∠BED = m∠BCA ⇒ corresponding angles

* Lets use similarity to prove that Δ BDE similar to Δ BAC

- In triangles BDE and BAC

∵ m∠BDE = m∠BAC

∵ m∠BED = m∠BCA

∵ ∠B is a common angle in the two triangles

∴ Δ BDE ≈ Δ BAC ⇒ by AAA

∴ Their corresponding sides are proportion

∴ $\frac{BD}{BA}=\frac{DE}{AC}=\frac{BE}{BC}$

∵ AB = 16 cm , AC = 20 cm , DE = 15 cm

∴ $\frac{BD}{16}=\frac{15}{20}$

∴ $\frac{BD}{16}=\frac{3}{4}$

- By using cross multiplication

∴ 4 BD = 16 × 3

∴ 4 BD = 48

- Divide both sides by 4

∴ BD = 12 cm

∵ Point D divides side AB into two parts BD and DA

∴ AB = BD + AD

∵ AB = 16 cm

∵ BD = 12 cm

∴ 16 = 12 + AD

- Subtract 12 from both sides

∴ AD = 4 cm

* The length of AD is 4 cm

4 0

3 years ago

Read 2 more answers

If a+3b=13 and a+b=5 the value of b is

hoa [83]

Answer:b=4

Step-by-step explanation:

7 0

3 years ago

What are the common factors of 18 and 27?

Natasha_Volkova [10]

Answer:

1, 2, 3, 9

Step-by-step explanation:

They are all factors of 18 and 27.

4 0

3 years ago

Read 2 more answers