Question

If f(x)=6x^3-4 and g(x)=2x+2 find (f-g) (x) a.6x^2-2x-2 b.6x^3-2x-6 c.2x-5x^3 4x^3-6

Answer 1

(f-g)(x)=f(x)-g(x)=
(6x³-4)-(2x+2)=
6x³-4-2x-2=
6x³-2x-4-2=
6x³-2x-6

B is answer

Answer 2

Answer:

B is correct

Step-by-step explanation:

We are given two function f(x) and g(x). We need to calculate (f-g)(x)

$f(x)=6x^3-4$

$g(x)=2x+2$

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(6x^3-4)-(2x+2)$

Using Distributive property (-2x-2)

$(f-g)(x)=6x^3-4-2x-2$

Combine like terms (-4-2=-6)

$(f-g)(x)=6x^3-2x-6$

Thus, (f-g)(x)=6x³-2x-6.