So first create and define your variables:
Z = amount of zebra fish
N = amount of neon tetras
Now create your equations:
2z+2.15n=31.20
z+n=15
This is your system. There are multiple methods to use but in this problem I’ll use the substitution method by simplifying the bottom equation.
2z+2.15n=31.20
z=15-n
Now I’ll plug the bottom equation into the top one.
2(15-n)+2.15n=31.20
And just solve from here.
30-2n+2.15n=31.20
0.15n=1.20
n=8
So he bout 8 neon tetras, and 15-8= 7, so he bought 7 zebra fish
Hi I don’t know just want point
<span>x = 18 and the length of each side of the triangle is 29.
This is a matter of reading the descriptions and converting to mathematical notation.
"QRS is an equilateral triangle"
We now know that all three sides of the triangle have the same length.
"If QR is seven less than twice x". So we can write
QR = 2x - 7
"RS is 61 less than 5 times x". So we can write
RS = 5x - 61
"QS is 11 more than x". And we can write
QS = x + 11
And because we already know that they all have the same length, then we can set those equations equal to each other. Let's just pick 2 of them. Will use the length of QR and QS because they look the simplest and then will solve for x.
QR = 2x - 7
RS = 5x - 61
QS = x + 11
2x - 7 = x + 11
x - 7 = 11
x = 18
So we now know that x = 18. Let's check to make sure all three equations have the same value.
QR = 2x - 7 = 2*18 - 7 = 36 - 7 = 29
RS = 5x - 61 = 5*18 - 61 = 90 - 61 = 29
QS = x + 11 = 18 + 11 = 29
And they all are equal, so 18 is the correct value for x.</span>
Answer:
dy/dx = x^sin(x) * (sin(x)/x + cos(x) * lnx)
Step-by-step explanation:
∵ y = x^sin(x)
∴㏑y = ㏑(x^sin(x)) = sinx * ㏑x --- by differentiating both sides with respect to x
(1/y)* dy/dx = sin(x)/x + cos(x) lnx
dy/dx = x^sin(x) * (sin(x)/x + cos(x) * lnx)