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pashok25 [27]
4 years ago
7

Julio is drawing tiles from a bag of tiles like the one shown below.

Mathematics
1 answer:
DaniilM [7]4 years ago
3 0
The answer might be D or C I don’t kno for sure yet but those are the main ones you gotta worry about !
You might be interested in
True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

7 0
4 years ago
Read 2 more answers
A vehicle purchased for $
Nataly [62]

Answer:

$10,870

Step-by-step explanation:

we can multiply the initial value (27500) by (1-.06), or 0.94, raised to the 15th power

27500(.94)^15 = 10,870.52

6 0
3 years ago
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral.
Nadusha1986 [10]

Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.

Explanation:

The conjecture, #angleA and angleC# allows us to write the following equation:

#angleA + angleC=180^@#

Substitute the equivalent expressions in terms of x:

#x+2+ x-2 = 180^@#

#2x = 180^@#

#x = 90^@#

From this we can compute the measures of all of the angles.

#angleA=92^@#

#angleB=100^@#

#angleC=88^@#

<span>#angleD= 80^@#</span>

4 0
3 years ago
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
Can someone help please
larisa [96]

Answer:I got the pic over here

Step-by-step explanation:

5 0
3 years ago
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