All categories

3 years ago

If a baby weighed 3 and 3/8 how many more pounds would it have to gain to reach 5 1/2 pounds

1 answer:

Volgvan3 years ago

6 0

First, get common denominators
At the same time, turn these into mixed numbers
27/8 + x = 44/8
Subtract 27/8 from both sides
x = 2 1/8 pounds
Let’s x be how many more pounds the baby needs

You might be interested in

2Plss need help, timed

stiv31 [10]

The firefighters would not be able to reach the cat because the ladder is only 35 cm tall and the cat is 39m up (I HOPE THIS ACTUALLY HELP IF IT DOES NOT I HOPE SOMEONE CAN HELP YOU)

8 0

2 years ago

Can somebody give me the answer to this question please

Alex

the answer is either A or B, probably C, maybe D. I know it's one of those

6 0

2 years ago

Read 2 more answers

Dots sells a total of 277 T-shirts ($2) and shorts ($3). In April, total sales were $656.

icang [17]

Answer:

Shorts = 112 and t shirts = 165

Step-by-step explanation:

Let S = shorts

Let T = t shirts

T + S = 277

$2T + $3S = $656

-2(T + S) = 277 so -2T -2S = -544

2T + 3S = 656 so 2T + 3S = 656

------------------------

SO: (subtract T's cancel out) 1S = 112

divide by 1 so S = 112

Plug S into the top equation: T + s = 277 T + 112 = 277 so T = 165

5 0

2 years ago

Which number is irrational A. 2.7 B. -2. 7 C. 2/7 D. √7

pashok25 [27]

Answer:

Step-by-step explanation:

because $\sqrt{7}$ is radical

6 0

3 years ago

Read 2 more answers

You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.

RUDIKE [14]

Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

$xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}$

Substituting for y into the equation for the length of fencing needed, we have

$P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}$

For the amount of fencing to be minimum, then

$\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24$

Now, recall that

$y= \frac{288}{x} = \frac{288}{24} =12$

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.

8 0

3 years ago