A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an
d then a yellow marble is 0.37, and the probability of selecting a blue marble on the first draw is 0.55. What is the probability of selecting a yellow marble on the second draw, if the first marble drawn was blue?
A) 18%
B) 20%
C) 46%
D) 67%
blue marbles y = yellow marbles Sum = b+y The <span>chance of a blue marble being drawn first is: b / (b+y) = 0.55 </span>The <span>chance of a blue marble being drawn first then a yellow next is: </span>b / (b+y) * y / (b+y-1) = 0.37 This can be solve easily by using a theorem of Bayes 0.37/0.55 = .67 or 67%
