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Musya8 [376]
3 years ago
7

4) A 60 kg astronaut pushes against a 120 kg satellite with a force of 15 N. How much force does the satellite exert on the astr

onaut?
Mathematics
1 answer:
Mkey [24]3 years ago
7 0

Answer:

30n

Step-by-step explanation:

You might be interested in
Y=6x-11 -2x-3y=-7 solve each system of equation by substitution
Anit [1.1K]

Answer:

(2, 1 )

Step-by-step explanation:

Given the 2 equations

y = 6x - 11 → (1)

- 2x - 3y = - 7 → (2)

Substitute y = 6x - 11 into (2)

- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side

- 2x - 18x + 33 = - 7

- 20x + 33 = - 7 ( subtract 33 from both sides )

- 20x = - 40 ( divide both sides by - 20 )

x = 2

Substitute x = 2 into (1) for corresponding value of y

y = 6(2) - 11 = 12 - 11 = 1

Solution is (2, 1 )

5 0
3 years ago
I"M SO DONE WITH BOTS SOMEBODY PLEASE HELP ME
Mice21 [21]
<h3><u>Answer:</u></h3>
  • Your answer would be "30".
<h3><u>Step-by-step explanation:</u></h3>
  • 2x + 20 = 3x - 10 [Corresponding Angles]
  • => 10 + 20 = 3x - 2x
  • => 30 = x
<h3><u>Conclusion:</u></h3>

Therefore, your answer would be "30".

Hoped this helped.

BrainiacUser1357

5 0
2 years ago
Carmen rolls a cube with sides labeled A, B, C, D, E, and F.
Sav [38]
The number of possible outcomes is 29. ! hope this help hun <3
5 0
3 years ago
Factor this expression and show the steps<br><br>12x^2+14x-6<br>​
Minchanka [31]

\boxed{\bold{2\left(3x-1\right)\left(2x+3\right)}}

\bold{----------------------------------}

  • \bold{Factor \ Out \ Common \ Term \ 2: \ 2\left(6x^2+7x-3\right)}

\bold{2\left(6x^2+7x-3\right)}

  • \bold{Factor \ 6x^2+7x-3: \ \left(3x-1\right)\left(2x+3\right)}

\bold{2\left(3x-1\right)\left(2x+3\right)}

\boxed{\bold{Eclipsed}}

6 0
3 years ago
Find all the missing values to make the equation true
Georgia [21]

The missing value in the logarithm are as follows:

  • log₃ 7 - log₃ 2 = log₃ (7 / 2)
  • log₉ 7 + log₉ 4 =  log₉ 28
  • log₆ 1 / 81  =  
  • - 4 log₆ 3

<h3>How to solve logarithm?</h3>

Using logarithm rule,

logₐ b - logₐ c = logₐ (b / c)

logₐ b + logₐ c = logₐ (b × c)

Therefore,

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ (7 × 4) =  log₉ 28

log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ =  - 4 log₆ 3

learn more on logarithm here: brainly.com/question/24515212

#SPJ1

4 0
2 years ago
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