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3 years ago

What is the range of the exponential function f(x)=2•7x

Mathematics

1 answer:

sergeinik [125]3 years ago

5 0

f(x) cannot be 0 or less than zero, but can approach+ infinity

Answer is (0, ∞)

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Select the equation that represent the phrase: Tom has three more dollars than Yesinia - T 37 Y = 3T Y=3+ TSY

Brut [27]

Answer:

bruh

Step-by-step explanation:

thank u

4 0

3 years ago

9<br> 4<br> 5<br> 12<br> Find the area of the given triangle

Nezavi [6.7K]

Answer:

24 units²

Step-by-step explanation:

8 0

3 years ago

The product of a linear monomial and a linear binomial is a

oksian1 [2.3K]

Answer:

The product of a linear monomial and a linear binomial is a second degree binomial

Step-by-step explanation:

Examples of linear monomials are:

Examples of linear binomials are:

2x+y

x-y

3a+b

x+1

When we take the product of a linear monomial and a linear bbinomial we obtain:

2a(3a+b)=6a²+2ab

y(x+1)=xy+y

y(x-y)=xy-y²

These are all second degree binomials.

4 0

4 years ago

Hope Amelia Solo, the American soccer goalkeeper, World Cup champion and two-time Olympic gold medalist, allows goals at a rate

Nuetrik [128]

Answer:

3.70% probability she allows more than one goal

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

X~Pois(0.3)

This means that $\mu = 0.3$

In her next match, what is the probability she allows more than one goal?

Either she allows at most one goal, or she allows more than one goal. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 1) + P(X > 1) = 1$

We want $P(X > 1)$ . So

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.3}*(0.3)^{0}}{(0)!} = 0.7408$

$P(X = 1) = \frac{e^{-0.3}*(0.3)^{1}}{(1)!} = 0.2222$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.7408 + 0.2222 = 0.9630$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.9630 = 0.0370$

3.70% probability she allows more than one goal

3 0

3 years ago

What is the product of the perpendicular lines

sattari [20]

Answer:

-1 i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers