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kotykmax [81]
3 years ago
11

What is the value of the function at x=−2?

Mathematics
2 answers:
jasenka [17]3 years ago
6 0
Y=2
I hope I helped..
muminat3 years ago
4 0

Answer:

y = 2

Step-by-step explanation:

When we have graph is given also one value from x and y is given then for finding the other value, We simply see the line where x = -2 is graphed and then we will see what is the value of y there.

Here at x = -2, y = 2 this is clearly apparent from the graph.

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The difference between $500.02 - $79.3 add explanation if possible
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Simplify the expression:<br> 3p+–p
Aleks04 [339]

Answer:

3p-p

Step-by-step explanation:

I always think of the negative sign out ruling the positive sign so let's do that for the -p part.

3p-p is what it becomes

Your question says simplify but just in case you want the answer here it is:

-p is also the same as -1p

So therefore we have

3p-1p

And we subtract the coefficients and keep the variable

2p would be your answer but once again I don't know if you wanted that so just to be sure I put 3p-p as my "answer".

5 0
2 years ago
You and a friend plan to see 2 movies over the weekend. You can choose from 6 comedy, 2 drama, 4 romance, 1 science fiction, or
Debora [2.8K]
There are a total of 16 movies to choose from and 6 of them are comedy. This means that you have a 38% of choosing comedy. But the chances of you not choosing comedy is 62%. And since your friend is also choosing, the chance of neither of you not choosing is cut in half.

So, the final answer of neither of you choosing comedy is 31%

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7 0
3 years ago
How do you evaluate sin(13π/12)?
Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

sin(13pi/12) = - sqrt[2 - sqrt[3]]/2

7 0
3 years ago
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