I hope this helps but cars, phones and computers.
Answer:
See explanation below
Explanation:
Named ranges are a very important tool in Microsoft Excel. It is used in assigning a name to a particular number of cells. It is great for automation and makes formula much easy to understand and use.
One way to create named ranges is theory the Name Box.
To create named ranges in the design marketing sheet we do this;
1) We click on cell B8 and then navigate to the name box at the top right corner of the sheet just above the column A.
•The name box is where the cell address of any cell that is active is displayed.
•You would see that “B8” is displayed on the name box.
• Double click on the name box and type in the appropriate name, in this case - Design_Fee.
• Press enter and you have your named range.
You do the same for the other named ranges.
Note that: Named ranges must contain letters, numbers or underscore.
They should use fiber cable because it is faster and more reliable
I would recommend A. Quickly on the left and move ahead of it because you should always pass on the left and seeing as it is a large truck, you would want to get ahead of it ASAP.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4