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blsea [12.9K]
3 years ago
8

The ________ is the easy way to insert a new slide between existing slides.

Computers and Technology
1 answer:
Tema [17]3 years ago
7 0
What is the subject about?
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Which of the following is not an advantage of concurrent design?
viva [34]

The answer I believe is B

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Create a poem about MS powerpoint presentation
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You could use poem generator online or see samples and change some words
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2 years ago
Byte pair encoding is a data encoding technique. The encoding algorithm looks for pairs of characters that appear in the string
erica [24]

Answer:

C. Byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.

Explanation:

Byte pair encoding is a form of encoding in which the most common pairs of consecutive bytes of data are replaced by a single byte which does not occur within the set of data.

For example, if we has a string ZZaaAb, it can be encoded if the pairs of string ZZ are replaced by X and the second pair by Y. So, our data now becomes XYAb.

To get our original data, that is decode it, we just replace the data with the keys X = ZZ and Y = aa thus allowing our original data to be restored.

Since our original string is restored without loss of data, it implies that <u>byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.</u>

8 0
2 years ago
Write a program in C++ to implement bubblesort using the swap function ?
marishachu [46]

C++ program for implementation of Bubble sort  

#include <bits/stdc++.h>  

using namespace std;  

 void swap(int *x, int *y)  /*Defining Swap function of void return type*/

{  

  int temp = *x;  //Swaping the values  

   *x = *y;  

   *y = temp;  

}  

void bubbleSort(int array[], int n) /*Defining function to implement bubbleSort  */

{  

  int i, j;  

  for (i = 0; i < n-1; i++)      

      for (j = 0; j < n-i-1; j++)  /*The last i components are already in location  */

      if (array[j] > array[j+1])  

          swap(&array[j], &array[j+1]);  //Calling swap function

}  

int main()  //driver function

{  

   int array[] = {3, 16, 7, 2, 56, 67, 8}; //Input array  

   int n = sizeof(array)/sizeof(array[0]);  //Finding size of array

   bubbleSort(array, n); //Function calling  

   cout<<"Sorted array: \n";  

   for (int i = 0; i < n; i++)  //printing the sorted array

       cout << array[i] << " ";  

   cout << endl;  

 return 0;  

}  

<u>Output</u>

Sorted array:  

2 3 7 8 16 56 67

3 0
3 years ago
Assume a computer uses pipelining of 9 stages. Each stage demands 3 clock cycles to finish its task. How many clock cycles are n
serg [7]

Answer:

Explanation:

b) Each stage requires one clock cycle; ... Calculate how many clock cycles will take execution of this segment on the regular (non- pipelined) ... Instruction. Clock cycle number . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 ... It is possible ... It means that all stages of 5-stage pipeline are always busy (no stalls) during the task.

8 0
2 years ago
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