Answer: 400
Step-by-step explanation: So it’s Length, width, and height. so:
1: 10 times 8= 80
2= 80 times 5= 400u2
Be sure to box your answer.
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
Answer:
f'(x) = -6/x³
Step-by-step explanation:
We are given;
f(x) = 3/x²
Using quotient rule, we can write as;
f(x) = g(x)/h(x)
To find the derivative, from quotient rule, we can write;
f'(x) = [(h(x)*g'(x)) - (g(x)*h'(x))]/(h(x))²
g'(x) = 0
h'(x) = 2x
Thus;
f'(x) = [(x²*0) - (3*2x)]/(x²)²
f'(x) = -6x/x⁴ = -6/x³
f'(x) = -6/x³
Answer: It's B
Step-by-step explanation:
