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PSYCHO15rus [73]
4 years ago
12

Solve the equation and check your solution -(3y+2) -(-2y-4)=0

Mathematics
1 answer:
Gre4nikov [31]4 years ago
7 0

Answer:

y=2

Step-by-step explanation:

-(3y+2) -(-2y-4)=0

Distribute the minus signs

-3y -2 +2y +4 = 0

Combine like terms

-y +2 = 0

Add y to each side

-y+y +2 = 0+y

2=y

Check

-(3*2+2) -( -2*2-4) =0

-(6+2) -(-4-4)=0

-8 - (-8) =0

-8+8 =0

0=0

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I’m failing, please help me!!!
Zigmanuir [339]

Answer: 400

Step-by-step explanation: So it’s Length, width, and height. so:

1: 10 times 8= 80

2= 80 times 5= 400u2

Be sure to box your answer.

4 0
3 years ago
For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

5 0
3 years ago
Use the quotient rule to find the derrivatives of 3/x^2​
Hunter-Best [27]

Answer:

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Step-by-step explanation:

We are given;

f(x) = 3/x²

Using quotient rule, we can write as;

f(x) = g(x)/h(x)

To find the derivative, from quotient rule, we can write;

f'(x) = [(h(x)*g'(x)) - (g(x)*h'(x))]/(h(x))²

g'(x) = 0

h'(x) = 2x

Thus;

f'(x) = [(x²*0) - (3*2x)]/(x²)²

f'(x) = -6x/x⁴ = -6/x³

f'(x) = -6/x³

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