3 years ago

The half-life of radium is 1690 years. If 20 grams are present now, how much will be present in 250 years?

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

18.05 g

Step-by-step explanation:

The multiplier of the initial quantity is ...

(1/2)^(t/1690)

so, for t=250, this becomes ...

(1/2)^(250/1690) ≈ 0.902545

Then the quantity remaining of the initial 20 g is ...

(20 g)(0.902545) ≈ 18.05 g

You might be interested in

What is 8/30 in simplest form?

Free_Kalibri [48]

8/30
= (8/2) / (30/2)
= 4/15

8/30 in its simplest form is 4/15~

5 0

2 years ago

Read 2 more answers

A line extending from the lower left to the upper right has this type of slope

Kitty [74]

A line extending from the lower left to the upper right has a positive slope.

7 0

3 years ago

Read 2 more answers

4. Find each missing length to the nearest tenth. 3 7

ale4655 [162]

I believe the answer 7.6

3 0

2 years ago

The equation of the line with slope 4 and y -intercept 4 can be written in the form y = m x + b where the number m is: the numbe

VLD [36.1K]

Answer: $m:4; \ b=4$

Step-by-step explanation:

Given

Slope is 4

Y-intercept is 4

For the slope-intercept form of line i.e. $y=mx+b$

$m=\text{slope of line}\\b=\text{Y-intercept of the line}$

So, we can write

$y=4x+4$

$m:4; \ b=4$

8 0

2 years ago

Solve x^2-2x-3=0 by graphing A. X=-1,3 B. X=-1,3 C. No solution D. X=-1,3

ioda

The answer is 3, -1.

7 0

3 years ago

Read 2 more answers

The​ half-life of radium is 1690 years. If 20 grams are present​ now, how much will be present in 250 ​years?

The half-life of radium is 1690 years. If 20 grams are present now, how much will be present in 250 years?