Question

When rolling fair number cube with numbers 1 through 6 what is the probability of rolling a number less than 3

Answer 1

Each face of the cube has an equal $\dfrac16$ probability of being rolled. There are 2 numbers on the cube less than 3 (1 and 2). The event of rolling a 1 and the event of rolling a 2 are mutually exclusive (you can't roll both faces at once), so

$P(1\text{ or }2)=P(1)+P(2)=\dfrac16+\dfrac16=\dfrac13$

Answer 2

Answer:

1/3

Step-by-step explanation:

There are 2 numbers on a die that are less then 3. That's 2/6 or 1/3. There's a 1/3 chance that the number will be less then 3.