Question

I will Make Brainliest ! Plz solve those 5 Question on the Picture.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$x\in [-1 \ ; \ 1) \ \cup \ (1 \ ;\ 3] \ \ or \ \ \left [ \begin{array}{ccc} x\geq -1 \\ \!\!\!\!x\neq 1 \\ \!\!\!\!x\leq 3\end{array}$

Step-by-step explanation:

$\displaystyle y=2x^2+2 \ \ ; \ \ -2\leqslant x\leqslant 4 \\\\ Find \ intwerval \ if : \\\\ -10} \atop {(x-3)(x+1) \leq 0}} \right. \Leftrightarrow \\\\\\ \left [ {{x\neq 1} \atop {(x-3)(x+1)\leq 0}} \right. \ \ ; \ \ and \ \-2\leqslant x\leqslant 4 \\\\ Then: \\\\ signs : +++[-1]---(1)---[3] +++$

                           \\\\\\\\\\\\\\\\\

$x\in [-1 \ ; \ 1) \ \cup \ (1 \ ;\ 3]$

Let's check whether  $-2\leqslant x\leqslant 4$    or [-2 ; 4 ] is included in the interval

----------[-1]--------(1)--------[3]------

       |                  |

       |                  |

---[-2]---[-1]---------(1)-----------[3]--------[4]

           /////////////

The interval enters the interval x completely then the answer is :

$x\in [-1 \ ; \ 1) \ \cup \ (1 \ ;\ 3] \ \ or \ \ \left [ \begin{array}{ccc} x\geq -1 \\ \!\!\!\!x\neq 1 \\ \!\!\!\!x\leq 3\end{array}$