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KonstantinChe [14]
3 years ago
9

I will Make Brainliest ! Plz solve those 5 Question on the Picture.​

Mathematics
2 answers:
Temka [501]3 years ago
5 0

Step-by-step explanation:

met I'd => 86189778400

pas code => g0cg6V

come on g met => spd-mwbz-een

kifflom [539]3 years ago
4 0

Answer:

x\in [-1 \ ; \ 1)   \ \cup  \ (1 \  ;\  3] \ \ or  \ \ \left [ \begin{array}{ccc}  x\geq -1 \\ \!\!\!\!x\neq 1 \\ \!\!\!\!x\leq 3\end{array}

Step-by-step explanation:

\displaystyle y=2x^2+2  \ \  ;   \  \  -2\leqslant  x\leqslant 4  \\\\  Find \  intwerval \  if : \\\\  -10} \atop {(x-3)(x+1) \leq 0}} \right.   \Leftrightarrow \\\\\\ \left [ {{x\neq 1} \atop {(x-3)(x+1)\leq 0}}  \right.  \ \ ; \ \ and  \ \-2\leqslant  x\leqslant 4 \\\\ Then: \\\\ signs : +++[-1]---(1)---[3]  +++ \\\\

<h3>                            \\\\\\\\\\\\\\\\\</h3><h3>x\in [-1 \ ; \ 1)   \ \cup  \ (1 \  ;\  3]</h3>

Let's check whether  -2\leqslant  x\leqslant 4    or [-2 ; 4 ] is included in the interval

----------[-1]--------(1)--------[3]------

<h2>        |                  |</h2><h2>        |                  |</h2>

---[-2]---[-1]---------(1)-----------[3]--------[4]

<h2>            /////////////</h2>

The interval enters the interval x completely then the answer is :

x\in [-1 \ ; \ 1)   \ \cup  \ (1 \  ;\  3] \ \ or  \ \ \left [ \begin{array}{ccc}  x\geq -1 \\ \!\!\!\!x\neq 1 \\ \!\!\!\!x\leq 3\end{array}

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