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yuradex [85]
3 years ago
13

Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a

10% discount.What is the total price of 4 1/2 pounds of apples this week at the grocery store
Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

The total price of 4\frac{1}{2}  pounds of apples is <u>$6.48</u>.

Step-by-step explanation:

Given:

Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a 10% discount.

Now, to find the total price of 4 1/2 pounds of apples this week at the grocery store.

The price of apples at a grocery store last week was = $1.60 per pound.

This week apples at the same grocery store is on sale of 10% discount.

Thus, the price of apples at a grocery store this week is:

1.60-10\%\ of\ 1.60.

=1.60-\frac{10}{100} \times 1.60

=1.60-0.16

=\$1.44.

So, the price of apples per pound this week is $1.44.

Now, to get the total price of 4\frac{1}{2} pounds of apples by using unitary method:

If 1 pound of apples cost = 1.44.

Then, \frac{9}{2} pound of apples cost = 1.44\times \frac{9}{2}

=1.44\times 4.5

=\$6.48.

Therefore, the total price of 4\frac{1}{2}  pounds of apples is $6.48.

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Option B: O(0,0), S(0,a), T(2a,2a), W(a,0)

Now, we shall find the length of the square,

\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}

This is not a square because the lengths are not equal.

Option C: O(0,0), S(0,2a), T(2a,2a), W(2a,0)

Now, we shall find the length of the square,

\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}

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Thus, the correct answers are option a and option d.

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