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3 years ago

Why can’t -3/4 be a integer

Mathematics

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

It can't be an integer because it's not a whole number. Integers are whole numbers, either positive or negative.

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Are the graphs of the lines in the pair parallel? Explain.<br><br> y = 3/7x + 11<br> –3x + 7y = 13

Kobotan [32]

Yes they will be parallel. Now you try to solve it.

5 0

3 years ago

Read 2 more answers

Help! will give points for brainliest

Misha Larkins [42]

Answer:

Step-by-step explanation:

Choose two outputs that are 3 values apart and find their ratio:

... f(3)/f(0) = 216/8 = 27

6 0

3 years ago

Help plz question is in the photo

mixas84 [53]

Answer:

A. Trinomial

Step-by-step explanation:

It says it's a polynomial and that based on the number of terms. So right then you can cancel out cubic and quadratic because they aren't polynomials. Also:

Cubic is just a variable with the exponent of 3. Examples:

$x^3,y^3,z^3$

Binomial is a polynomial with 2 terms. Examples:

$5x+3; 6x+2; x+7$

A quadratic has a division sign.

8 0

3 years ago

A vector is used to express a car's change in position, or displacement, by tracking its motion over a large area defined by a c

Mnenie [13.5K]

Answer:

The correct answer is option C: (8, 14).

Step-by-step explanation:

The car's displacement in vector form can be found by subtracting the initial points from the final points.

Initial: (x₁, y₁) = (-3, -5)

Final: (x₂, y₂) = (5, 9)

For the x-coordinate, we have:

$d_{x} = x_{2} - x_{1} = 5 - (-3) = 8$

And for the y-coordinate, we have:

$d_{y} = y_{2} - y_{1} = 9 - (-5) = 14$

The car's displacement in vector form is:

$d = (d_{x}, d_{y}) = (8, 14)$

Therefore, the correct answer is option C: (8, 14).

I hope it helps you!

7 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

3 years ago