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iris [78.8K]
3 years ago
6

Why can’t -3/4 be a integer

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

It can't be an integer because it's not a whole number. Integers are whole numbers, either positive or negative.

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Are the graphs of the lines in the pair parallel? Explain.<br><br> y = 3/7x + 11<br> –3x + 7y = 13
Kobotan [32]
Yes they will be parallel. Now you try to solve it.
5 0
3 years ago
Read 2 more answers
Help! will give points for brainliest
Misha Larkins [42]

Answer:

27

Step-by-step explanation:

Choose two outputs that are 3 values apart and find their ratio:

... f(3)/f(0) = 216/8 = 27

6 0
3 years ago
Help plz question is in the photo
mixas84 [53]

Answer:

A. Trinomial

Step-by-step explanation:

It says it's a polynomial and that based on the number of terms. So right then you can cancel out cubic and quadratic because they aren't polynomials. Also:

Cubic is just a variable with the exponent of 3. Examples:

x^3,y^3,z^3

Binomial is a polynomial with 2 terms. Examples:

5x+3; 6x+2; x+7

A quadratic has a division sign.

8 0
3 years ago
A vector is used to express a car's change in position, or displacement, by tracking its motion over a large area defined by a c
Mnenie [13.5K]

Answer:

The correct answer is option C: (8, 14).

Step-by-step explanation:

The car's displacement in vector form can be found by subtracting the initial points from the final points.    

Initial: (x₁, y₁) = (-3, -5)

Final: (x₂, y₂) = (5, 9)          

For the x-coordinate, we have:  

d_{x} = x_{2} - x_{1} = 5 - (-3) = 8

And for the y-coordinate, we have:

d_{y} = y_{2} - y_{1} = 9 - (-5) = 14

The car's displacement in vector form is:

d = (d_{x}, d_{y}) = (8, 14)  

Therefore, the correct answer is option C: (8, 14).

I hope it helps you!                        

7 0
3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
sineoko [7]
ANSWER

The scale factor is
2.5

EXPLANATION

The given triangle has vertices,

A(0,0),B(0,4),\:and\:C(6, 0).

The vertices of the image triangle is,

A'(0,0),B'(0,10),\:and\:C'(15, 0).

The scale factor is given by

k = \frac{image \: length}{object \: length}

So we can use any of the corresponding sides to determine the scale factor,

k = \frac{|A'B'|}{ |AB|}

k = \frac{ |10 - 0| }{ |4 - 0|}

k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5

Or

k = \frac{|A'C'|}{ |AC|}

k = \frac{ |15 - 0| }{ |6 - 0|}

k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5


Or

k=\frac{|B'C'|}{|BC|}

k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}

k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5

The correct answer is C
3 0
3 years ago
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