Un bloque de 65 kg en un plano horizontal, es empujado por una fuerza de 380 N a un ángulo de 15° respecto a la horizontal. Si e
l coeficiente de fricción cinética es de 0.3, ¿Que distancia recorrerá cuando transcurran 10 segundos de ser aplicada la fuerza, si parte del reposo?
1 answer:
Answer:
ya karena kamu sangat cantik seperti model a
Step-by-step explanation:
thank me later bye ;)
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754/30= 25 with a 4 left over
if everyone gets the chance to ride there will have to be 26 rides
So C is the answer
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You have to use distributive property and multiply parentheses
Answer: x=14
Step-by-step explanation:
Subtract 2
from both sides of the equation.
X=16−2
Subtract 2
from 16
.
X=14
These are the two equation
10-2
13-5
I think that's the element on the second row and the first column which is 15.
