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Dafna11 [192]
3 years ago
10

Plz help me if u don’t mind A)65 B)72 C)79

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

it is B

Step-by-step explanation:

i hope this helps

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What is 15.083 rounded to the nearest tenth
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It is 15.100 because you just see if the hundredths is larger then five then just move the tenth up one more
                              
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How did American factories change during World War II to support the war effort?
shusha [124]

Step-by-step explanation:

Many Factories were converted into ammunition factorys and weapon factorys to support the war effort

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3 years ago
Read 2 more answers
The length of a rectangle is 1 unit more than the width. The area of the rectangle is 56 units. What is the width in units of th
Mandarinka [93]

Answer:

Width = 7units

Step-by-step explanation:

The area of a rectangle

A = h * w

A - area of a rectangle

h - height of a rectangle

w - width of a rectangle

Or

A = length * breadth

It's all the same

Given :

h = 1 + w

w = w

A = 56

56 = ( 1 + w) * w

56 = ( 1 + w)w

56 = w + w^2

56 = w^2 + w

w^2 + w - 56 = 0

Find a factor that can be multiplied to give -56

and added to give + 1

The factor is 8 and -7

Substitute 8w - 7w for w

w^2 + 8w - 7w - 56 = 0

( w^2 + 8w) - (7w - 56) = 0

w( w + 8) - 7( w + 8) = 0

( w - 7) = 0

( w + 8) =0

w - 7 = 0

w = 7

w + 8 = 0

w = -8

Since a side of any rectangle can not be negative

w = 7

The width of the rectangle is 7units

The length of the rectangle is 1 + w = 1 + 7 = 8units

4 0
3 years ago
Compute the area of the triangle height equals 6 cm base equals 12 cm what is the area
Aliun [14]

AREA =1/2 × base × height = 1/2×6×12=36cm^2

HOPE THIS WILL HELP U

3 0
3 years ago
How to get the answers?​
beks73 [17]

By inclusion/exclusion,

n(P' \cup Q) = n(P') + n(Q) - n(P' \cap Q)

We have

n(\xi) = n(P) + n(P') \implies n(P') = 28 - n(P)

so that

n(P'  \cup Q) = (28 - n(P)) + n(Q) - 2n(P) = 28 - 3n(P) + n(Q)

Now,

n(\xi) = 28 \implies n(P \cup Q) = 28 - 7 = 21

and by inclusion/exclusion,

n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)

Decompose Q into the union of two disjoint sets:

Q = (P \cap Q) \cup (P' \cap Q)

Since they're disjoint,

n(Q) = n(P\cap Q) + n(P'\cap Q) \implies n(Q) = n(P\cap Q) + 2n(P)

\implies n(P \cup Q) = n(P) + (n(P\cap Q) + 2n(P)) - n(P \cap Q)

\implies 21 = 3n(P)

\implies n(P) = 7

From the Venn diagram, we see there are 3 elements unique to P - by the way, this is the set P \cap Q' - so n(P\cap Q) = 7-3 = 4, and it follows that

n(Q) = n(P\cap Q) + 2n(P) = 4 + 2\times7 = 18

Finally, we get for (a)

n(P' \cup Q) = 28 - 3n(P) + n(Q) = 28 - 3\times7 + 18 = \boxed{25}

For (b), we have by inclusion/exclusion that

n(P \cup Q') = n(P) + n(Q) - n(P \cap Q') = 7 + 18 - 3 = \boxed{22}

5 0
2 years ago
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