Answer:
1, 2, 3, 4
Step-by-step explanation:
- 4 1/3·1 = 4 1/3 Good
- 7 1/3·2 2/5 = 22/3·12/5 = 110/15·36/15= 3960/225 = 17 3/5 Good
- 6 2/3·1/2 = (6 2/3)/2 = 3 1/3 Good
- 4 1/2·2 1/6 = 9/2·13/6 = 27/6·13/6 = 9 3/4 Good
- 5·3 1/4 = 20/4·13/4 = 16 1/4 Doesn't Work
Answer:5,000
Step-by-step explanation:
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer is 1
.............
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
