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3 years ago

5

Which table correctly shows all the sample spaces for tossing a coin and rolling an even number on a six-sided number cube?

1 answer:

kotykmax [81]3 years ago

4 0

Tossing a coin would be 1/2 because a coin has two sides and it has 1 out of two sides to land on the side you want it to land on. So that answer is 1/2. The dice rolling on an even number on a six-sided number cube would be 3/6. Which if you simplify it, it would be 1/2. The answer to both of them is 1/2!

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PLEASE HELP!! FAST :)

chubhunter [2.5K]

Since x³ = x^(1/3) you can say that

(x¹⁰)^(1/3) = x^10/3 = x^(3 + 1/3) =

x³ ·∛x

7 0

3 years ago

Find the area of a triangle with legs that are 9mm 6mm and 12mm

Sidana [21]

Here we are given the three sides of the triangle.

So we have Heron's formula to find its area.

Heron's formula is given by :

$A= \sqrt{S(S-A)(S-B)(S-C)}$

where A, B and C are sides of triangle and S is semi perimeter which is given by,

$S= \frac{A+B+C}{2}$

plugging values of A, B and C to find S

$S= \frac{9+6+12}{2}$

S=13.5

Now plugging values of A, B , C and S in Heron's formula

$A= \sqrt{13.5(13.5-9)(13.5-6)(13.5-12)}$

A=26.14 mm²

Answer: Area of triangle is 26.14 mm².

6 0

3 years ago

Help meeeeeee please :))))

maxonik [38]

Cant see the pic ya feel

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2 years ago

How do i do this pls help me

Delvig [45]

Answer:

$y = \frac{1}{7} x + 7$

Step-by-step explanation:

x-7y = -49

i) move x to the right-hand side and change its sign

-7y = -49-x

ii) change the signs on both sides of the equation

7y = 49+x

iii) divide both sides of the equation by 7

$\frac{7y}{7} = \frac{49}{7} + \frac{x}{7}$

$y = 7 + \frac{1}{7} x$

iv) use the commutative property to reorder the terms

* commutative property: a+b = b+a

$y = \frac{1}{7} x + 7$

3 0

3 years ago

41. You water your roses every sixth

ICE Princess25 [194]

Answer:

30

Step-by-step explanation:

because 6 × 5 equals 30 and when you're looking for when something's going to be the same you got to do what your numbers are times each other

5 0

3 years ago