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Novay_Z [31]
3 years ago
7

If rs || mn ,then the value of a is

Mathematics
2 answers:
vazorg [7]3 years ago
7 0
A = 74 because m<TRS and m<TMN are corresponding

hope it helps

...................


seraphim [82]3 years ago
4 0
40 is the answer =3 hope it works
You might be interested in
1.
bulgar [2K]

Answer:

8/9 will be left over

Step-by-step explanation:

3 7/9 + 5 1/3= 9 1/9

Now subtract the amount of paint needed by how much paint there is:

10- 9 1/9= 8/9

Therefore, 8/9 will be left over

Hope this helps

5 0
2 years ago
What is the answer for 4y^2=81
Elena L [17]
<span><u><em>Answer:</em></u>
either y = 4.5
or y = -4.5

<u><em>Explanation:</em></u>
To get the solution, we will need to isolate the y on one side of the equation.
<u>This can be done as follows:</u>
4y</span>²<span> = 81

</span>\frac{4y^2}{4} =  \frac{81}{4}
<span>
y</span>²<span> = 20.25

y = +/- </span>√(20.25)<span>
either y = +</span>√<span>(20.25) = 4.5
or y = -</span>√<span>(20.25) = -4.5

Since there are no restrictions on the value of y, therefore, both answers would be accepted

Hope this helps :)</span>
3 0
3 years ago
Read 2 more answers
PLEASE HELP WITH THIS
Kitty [74]
I think it is B -2 < x < 2
4 0
3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o
Ugo [173]
Alright,

(a) 2x+4(x-1)=2
2x+4x-4=2---- Distrubution of 4(x-1)
6x-4=2---- Combining like terms
6x=6---- Making -4 equal 0 by adding +4 to both sides
x=1---- Divide the coefficiant (6)

(b) 25-x=15-(3x+10)
25-x=15-3x-10----Distribute the -1
25-x=5-3x---- Combine like terms
25=5-2x---- Make -x equal 0 by adding +x to both sides
20=-2x---- Make 5 equal zero by subtracting 5 (or adding -5) to both sides
-10=x---- Divide by the coefficiant (-2)

(c) 4x= 2x+2x+5(x-x)
4x=2x+2x+5(0)---- Distribute. Alright this might look hard but realy it is 1x-1x so the answer is 0
4x=2x+2x---- 5 times 0 is 0
4x=4x---- Combine like terms
x=x ---- divide by the coefficiant

Alright! Hope this helps! ;)
4 0
3 years ago
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