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Margaret [11]
3 years ago
15

What is the primary goal and secondary goal of the Fried Liver Opening in chess? <br />

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0

Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.

Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.


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Answer:

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3 years ago
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In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

12 ⇒ <em>1st term</em>

15 ⇒ <em>2nd term</em>

18 ⇒ <em>3rd term</em>

21 ⇒ <em>4th term</em>

24 ⇒ <em>5th term</em>

27 ⇒ <em>6th term</em>

30 ⇒ <em>7th term</em>

33 ⇒ <em>8th term</em>

36 ⇒ <em>9th term</em>

39 ⇒ <em>10th term</em>

42 ⇒ <em>11th term</em>

45 ⇒ <em>12th term</em>

48 ⇒ <em>13th term</em>

51 ⇒ <em>14th term</em>

54 ⇒ <em>15th term</em>

57 ⇒ <em>16th term</em>

60 ⇒ <em>17th term</em>

63 ⇒ <em>18th term</em>

66 ⇒ <em>19th term</em>

<u>69 ⇒ </u><u><em>20th term</em></u>

<u><em></em></u>

This means that the 20th term of this arithemtic sequence is 69.

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