What is the primary goal and secondary goal of the Fried Liver Opening in chess?

1 answer:

3 0

Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.

Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.

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Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete

Svetllana [295]

Vertical angles are angles which are opposite to each other and have equal measures. With respect to the given proof, Angie completed the proof incorrectly.

Two angles are said to be vertical when they are opposite to one another and have equal measures. However, two angles are supplementary if they add up to 180°.

So, comparing Angie's and Becky's proofs, it can be deduced that from Angies proof:

1. Segment GH intersects segment AB at K (1. Given)

2. m∠AKG + m∠GKB = 180° (2. Definition of Supplementary Angles)

m∠GKB + m∠HKB = 180° (2. Definition of Supplementary Angles)

3. m∠AKG + m∠ GKB = m∠GKB + m∠HKB (3. Substitution Property)

4. m∠AKG = m∠HKB (4. Subtraction Property)

Note:

Step 2 should be Angle Addition Postulate, since:

m∠AKG + m∠GKB = 180°

m∠GKB + m∠HKB = 180°

So that;

m∠AKG + m∠GKB = m∠GKB + m∠HKB

Subtract m∠GKB from both sides to have;

m∠AKG = m∠HKB (which is the proof for step 4)

Therefore, Angie completed the poof incorrectly because of the properties of steps 2 and 4.

A diagram is herewith attached for more clarifications.

Visit: brainly.com/question/24529637

8 0

2 years ago

The number of point a baketball team cored ha 3,4, and 5 a factor. What i the leat number of point the team could have cored

Inga [223]

The least number of point the team could have scored is the LCM of the factors given = 60.

Factor 1 = 3

Factor 2 = 4

Factor 3 = 5

therefore, LCM

= 4 * 5 * 3 [because they don't have any factors in common]

= 60

The positive integers that can divide a number evenly are referred to as factors. Let's say we multiply two numbers to produce a result. The product's factors are the number that is multiplied.

Each number has a self-referential element. There are several examples of factors in everyday life, such putting candies in a box, arranging numbers in a certain pattern, giving chocolates to kids, etc. We must apply the multiplication or division method in order to determine a number's factors.

To learn more about LCM

brainly.com/question/20739723

#SPJ4

6 0

1 year ago

I need the answer to this please

11111nata11111 [884]

Answer:

Step-by-step explanation:

Alright, lets get started.

When two secants intersects outside a circle then the measure of the angle formed is half of the positive difference of the measures of the intercepted arcs. (Please refer the diagram I have attached)

Hence the measure of ∠1 is :

∠1= $\frac{1}{2}(100-30)$