The number of point a baketball team cored ha 3,4, and 5 a factor. What i the leat number of point the team could have cored

Mathematics

1 answer:

Inga [223]1 year ago

6 0

The least number of point the team could have scored is the LCM of the factors given = 60.

Factor 1 = 3

Factor 2 = 4

Factor 3 = 5

therefore, LCM

= 4 * 5 * 3 [because they don't have any factors in common]

= 60

The positive integers that can divide a number evenly are referred to as factors. Let's say we multiply two numbers to produce a result. The product's factors are the number that is multiplied.

Each number has a self-referential element. There are several examples of factors in everyday life, such putting candies in a box, arranging numbers in a certain pattern, giving chocolates to kids, etc. We must apply the multiplication or division method in order to determine a number's factors.

To learn more about LCM

brainly.com/question/20739723

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3 years ago

Suppose Ken has 25 coins and nickels and dimes only and has a total of a $1.65 how many of each coin does he have?

nikklg [1K]

$x-\ number\ of\ nickels\\
y-\ number\ of\ dimes\\\\
x+y=25 \ \ \ | x=25-y\\
0.05x+0.1y=1.65\\\\
0.05(25-y)+0.1y=1.65\\\\
1.25-0.05y+0.1y=1.65\\\\
1.25+0.05y=1.65\ \ \ | subtract\ 1.25\\\\
0.05y=0.4\ \ \ \ \ | divide\ by\ 0.05\\\\
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3 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;