To check for continuity at the edges of each piece, you need to consider the limit as
approaches the edges. For example,

has two pieces,
and
, both of which are continuous by themselves on the provided intervals. In order for
to be continuous everywhere, we need to have

By definition of
, we have
, and the limits are


The limits match, so
is continuous.
For the others: Each of the individual pieces of
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
the answer should be C. 5.27
9514 1404 393
Answer:
a. (-1/2, 5)
Step-by-step explanation:
The coefficients of x have opposite signs, so the x-terms can be eliminated by adding the two equations.
(2y -12x) +(3y +12x) = (16) +(9)
5y = 25 . . . . . . simplify
y = 5 . . . . . . . . .divide by 5
This matches only answer choice A.
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<em>Check</em>
The other part of answer choice A is x = -1/2. We can test this to make sure it works:
2(5) -12(-1/2) = 16
10 + 6 = 16 . . . . . . true, the selected answer works OK
Answer:
The baby would be 160 ounces.
Step-by-step explanation:
Answer:
11.7
Step-by-step explanation:
multiply RS by the scale factor to get R'S'