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Pepsi [2]
3 years ago
11

What is the answer to the word problem The cost of a gallon of orange juice is $3.50. What is the maximum number of containers y

ou can buy for $15?
Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer: 4

Step-by-step explanation: you use division, or your calculator, divide $15.00 by $3.50 and you get 4.28, so you can by 4 full gallons with $1.00 left over!

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Identify the diameter of the disc
Olegator [25]

radius = (4*10^2 + 24^2)/8*10 =

(400 + 576)/80=

976/80 = 12.2

diameter = 12.2 x 2 = 24.4

4 0
3 years ago
Round 0.868 to the nearest tenth.
Anna11 [10]

Answer: 0.9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Correct answers gets most brainiest!! :)
podryga [215]
Hello :)

Answer: x=11

Measure angel BAD= 122

Explanation:

To find X you have to make an equation

10x-49=5x+6

And then you solve for x

To find the angel measure of BAD, you have to add bac and cab to get bad

Bac= 10(11)-49 which equals 61

Cab= 5(11)+6=61

61+61= 122

Which is the measure of BAD

I hope this helps and have a wonderful rest of your night
6 0
3 years ago
Can I get some help on this I have so many assignments to do and I just want to go to sleep
AfilCa [17]
Hi! It’s me from your other post! Here’s my work for you! It’s been awhile since I’ve done this stuff so I’m really sorry if I get you a bad grade! I just wanted to help out:))

7 0
3 years ago
You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which
stellarik [79]
To model this situation, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
where
A is the final amount after t years 
P is the initial deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

For account A: 
We know for our problem that P=2000 and r= \frac{2.25}{100} =0.0225. Since the interest is compounded monthly, it is compounded 12 times per year; therefore, n=12. Lets replace those values in our formula:
A=2000(1+ \frac{0.0225}{12} )^{12t}

For account B:
P=2000, r= \frac{3}{100} =0.03, n=12. Lest replace those values in our formula:
A=2000(1+ \frac{0.03}{12} )^{12t}

Since we want to find the time, t, <span>when  the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span>2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000

Now that we have our equation, we just need to solve for t:
2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000
(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}
(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}&#10;{2}
ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})
12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})
t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})
t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}
17.47

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>
5 0
3 years ago
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