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Pie
3 years ago
9

Please help 60 Points!!!!!!!! my school is glitched :C

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

reload

Step-by-step explanation:

IgorLugansk [536]3 years ago
4 0

Answer:

its the two that are glitched because its not any of the other ones

Step-by-step explanation:

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The County Fair has to 2 ticket options.Option 1 has an entry fee of $5 and charges $0.65 per ride per ride. Option 2 has an ent
Ugo [173]

For 25 tickets total cost of option one and option two to be the same.

Step-by-step explanation:

Let us assume the total number of rides = m

for which BOTH options cost same.

Case: 1

The cost of entry fee  = $5

The cost per ride = $0.65

So, the cost of m rides  = m x ( Cost of 1 ride )  

=  m x ($0.65 ) = 0.65 m

Cost of purchasing m tickets in first ride  = Entry Fee + Per ticket cost

                                                                       = 5 +0.65 m    ..... (1)

Case: 2

The cost of entry fee  = $10

The cost per ride = $0.45

So, the cost of m rides  = m x ( Cost of 1 ride )  

=  m x ($0.45 ) = 0.45 m

Cost of purchasing m tickets in second ride  = Entry Fee + Per ticket cost

                                                                       = 10 +0.45 m    ..... (2)

Now, equating (1) and (2), we get:

5 +0.65 m = 10 +0.45 m

or, 0.20 m = 5

or, m = 5/0.20  = 25

or, m = 25

Hence, for 25 tickets total cost of option one and option two to be the same.

5 0
3 years ago
Three times a number subtracted from the product of fifteen and the reciprocal of a number
ASHA 777 [7]
To write the problem out as an equation, let 'n' equal your number. 

(15 x 1/n) - 3n
5 0
3 years ago
Read 2 more answers
Find x pleaseee :) :)
balu736 [363]

Answer:

it is 6

Step-by-step explanation:

3 0
2 years ago
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The maximum weight allowed per car on The Twister carnival ride is 263 pounds. Your friend weighs 86 pounds. To be able to ride
Kazeer [188]
Your weight:   x lb
Friend's wt.:  86 lb
Max wt. allowed:  263 lb

Then x + 86 ≤ 263, with x in lb.  You could weigh a max. of 177 lb and still be able to go on this ride.

4 0
3 years ago
A candy store owner wants to mix some candy costing $1.25 a pound
maria [59]

The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.

Given:

  • Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a pound
  • The resulting mixture should be 50 pounds of candy
  • The resulting mixture should cost $1.30 a pound

To find: The amount of candy costing $1.25 a pound that should be mixed

Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.

Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '50-x' pounds of candy costing $1.45 a pound.

Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '50-x' pounds of candy costing $1.45 a pound.

Accordingly, the total cost of the resulting mixture is 1.25x+1.45(50-x)

However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is 1.30 \times 50

Equating the total cost of the resulting mixture obtained in two ways, we get,

1.25x+1.45(50-x)=1.30 \times 50

1.25x+72.5-1.45x=65

0.2x=7.5

x=\frac{7.5}{0.2}

x=37.5

This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.

Learn more about cost of mixtures here:

brainly.com/question/17109505

4 0
3 years ago
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