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kodGreya [7K]
3 years ago
9

What is the length of side BC of the triangle? Enter your answer in the box.

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0
You set the equiangular triangles equal to each other
kondor19780726 [428]3 years ago
7 0

The triangle is an equiangular triangle so that means it must be an equilateral triangle.

3x - 3 = x + 8

2x = 11

x = 5.5

BC = 3(5.5) - 3

BC = 13.5

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Graphs which present the values on the horizontal axis and the number of times this occurs on the vertical axis are known as wha
Ivanshal [37]

Answer:

The horizontal axis represents TIME

Step-by-step explanation:

In a time-series plot, the horizontal axis represents time, and the vertical axis represents the value of the variable we are measuring. -The values of the variable are plotted at each of the times, then the points are connected with straight lines.

3 0
3 years ago
In an isosceles triangle two sides are equal. The third side is two less than twice the length of the two equal sides. The perim
pogonyaev

Answer:

The equal sides' length = 10

Third side length = 18

Step-by-step explanation:

Let the two equal sides' length be "x"

Let the third side length be "y"

Third side (y) is 2 LESS THAN TWICE the equal side, so we can write:

y = 2x - 2

The perimeter is 38. The perimeters is the sum of all three sides. So we can write:

x + x + y = 38

Replacing y with 2nd equation, we have:

x + x + (2x - 2) = 38

Now, we can solve this for x first:

x + x + (2x - 2) = 38\\x+x+2x-2=38\\4x=38+2\\4x=40\\x=10

Now, y is:

y = 2x - 2

y = 2(10) - 2

y = 20 - 2

y = 18

The equal sides' length = 10

Third side length = 18

3 0
3 years ago
2/3 of ___=6<br> Can you help me?
Artyom0805 [142]
9 is the answer because 1/3 = 3 
6 0
3 years ago
Read 2 more answers
What are the solution(s) of –x2 + 2x + 3 = x2 – 2x + 3?
Leviafan [203]
-x^2+2x+3=x^2-2x+3  add x^2 to both sides

2x+3=2x^2-2x+3  subtract 2x from both sides

3=2x^2-4x+3  subtract 3 from both sides

2x^2-4x=0  factor

2x(x-2)=0

So x=0 and 2
3 0
3 years ago
Read 2 more answers
PLEASE HELP ILL GIVE MEDALS AND MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!! NEEDS TO BE ALEGABRA 2 MEATHOD!!!!!!!!
mars1129 [50]
Hi there,
This is the original inequality equation:
\frac{x}{x+1} \ \textless \  \frac{x}{x-1}
So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.
\frac{x}{x+1} = \frac{x}{x-1}
Now, we multiply both sides by x + 1:
x= \frac{x^{2} +x}{x-1}
Then, we multiply both sides by x - 1:
x^{2} -x= x^{2} +x
Next, we subtract x² from both sides:
-x=x
After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1   </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1    </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0  </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1  </span><span>(Works in original inequality)
Therefore, the answer to your query is -1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>
4 0
3 years ago
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