Remember,
sin = op/hyp
cos = adj/hyp
tan = op/adj
For question 3 it would be B and C, because the adjacent side of angle x is 12, the hypotenuse is 37, and cos = adj/hyp. Also, the opposite side of angle z is 12, and the hypotenuse is 37, and sin = op/hyp. So both answers would be 12/37. You would do the same with question 4.
For 5, you would do the same thing. It would be D because you can only take the sin of angle 24, and x is a side. the opposite of 24 is x and the hypotenuse is 11, so sin 24 would be x/11. It is the same for problem 6.
So I’m only answering so I can ask you a question
There are 2 way to solve this.
one using Pythagoras theorem and 2nd using trigonometry
so lets solve it by both
using Pythagoras theorem we know
base^2 + perpendicular^2 = hypotanes^2
6^2 + x^2 = 12^2
36 + x^2 = 144
x^2 = 144- 36 = 108
x = √(108) = √( 2×2×3×3×3)
= (2×3) √ (3) = 6 √3
so answer is option 2
bow lets use trigonometry
we know
sin theta = perpendicular / hypotanes
sin 60 = x /12
x = 12 × sin 60
we kNow sin 60 = √3/ 2
so
x = 12×√3 /2 = 6√3
X y
-2 -3
-1 -1
0 1
1 3
2 5
i can’t graph it, but i hope this helps
