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3 years ago

What is the equivalent expression plzz help

Mathematics

1 answer:

Firlakuza [10]3 years ago

8 0

Correct answer: the first choice !

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PLEASE HELP ME! 22 POINTS!!!

Y_Kistochka [10]

Answer:

300 sq. cm.

Step-by-step explanation:

Do you need the explanation? If so, I can make one for you. You see, my hand is hurt, and it pains me to type.

5 0

3 years ago

Red and grey bricks were used to build a decorative wall. The number of red bricks and grey bricks was 5/2. There were 140 brick

ozzi

Answer:

100 red bricks

Step-by-step explanation:

Let's say red bricks is equal to 5x

Gray bricks is equal to 2x

We have an equation

2x + 5x = 140

= 7x = 140

Divide through by 7 to get the value of x

X = 140/7

X = 20

Red bricks = 5(x)

= 5(20)

= 100

Gray bricks = 2(x)

= 2(20)

= 40

Therefore in conclusion the number of red bricks is 100.

5 0

3 years ago

THe equation of the graph line is 2x-3y=12 what is the x-intercept of the graph

katrin2010 [14]

2x-3y=12

Make y substitute 0

2x-3(0)=12

2x= 12

X= 12-2

X= 10

X-intercept is 10

5 0

3 years ago

The map shows the location of the airport and a warehouse in a city. Though not displayed on the map, there is also a factory 10

kipiarov [429]

step 1

find the coordinates of the factory

the factory is 104 miles due north of the warehouse

the coordinates of the warehouse are (39,-52)

coordinates of the factory------> (39,-52+104)------> (39,52)

step 2

find the distance warehouse to airport

let

A coordinates of warehouse-------> A( 39,-52)

B coordinates of airport---------> B(-39,52)

C coordinates of factory-------> C(39,52)

distance AB=√[(52+52)²+(-39-39)²]------> distance AB=130 miles

step 3

find the distance airport to factory

B(-39,52)

C(39,52)

distance BC=√[(52-52)²+(39+39)²]-----> distance BC=39 miles

the total number of miles=distance AB+distance BC---> 130+39

the total number of miles=169 miles

<em>Thus</em> the answer is 169

4 0

3 years ago

Read 2 more answers

Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

garik1379 [7]

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

7 0

3 years ago