Answer: -8 and -4
This is something you do through trial and error. Making a list or a table like shown below might help.
Answer:

Step-by-step explanation:
The question is incomplete, as the angles of rotation are not stated.
However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself
We have:


Divide 360 degrees by the number of sides in each angle, then find the multiples.
<u>Nonagon</u>

List the multiples of 40

<u>Hexagon</u>

List the multiples of 60

List out the common angles



This means that, only a rotation of
will lift both shapes onto themselves, when applied to both shapes.
The other angles will only work on one of the shapes, but not both at the same time.
Answer:
to know the summation of angles: (n-2)*180
here (n) represent numbers of sides
12)we have 5 sides (n=5)
(5-2)*180=540
x=540-(105+135+92+87)=121
13)we have 8 sides (n=8)
(8-2)*180=1080
x=1080-(116+158+141+124+136+132+129)=144
I hope it will help
Answer:
Step-by-step explanation: This is the quadratic function:
h(x)=ax²+bx+c
We have two points:
(1,58)
(2,112)
Now, we calculate this quadratic funtion.
we assume that h(0)=0
Therefore:
a(0)²+b(0)+c=0
c=0
(1,58)
a(1)²+b(1)=58
a+b=58 (1)
(2,112)
a(2)²+b(2)=112
4a+2b=112
2a+b=56 (1)
With the equations (1) and (2) we make a system of equations:
a+b=58
2a+b=56
we can solve this system of equations by reduction method.
-(a+b=58)
2a+b=56
---------------------
a=-2
-2(a+b=58)
2a+b=56
-------------------
-b=-60 ⇒ b=60
The function is:
h(x)=ax²+bx+c
h(x)=-2x²+60x
Now find the height, in feet, of the rock after 10 seconds in the air.
h(10)=-2(10)²+60(10)
h(10)=-200+600=400
Answer: 400 ft.