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Mandarinka [93]
3 years ago
12

What is the least common multiple. Thanks.

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Before we start, find the LCM of 9, 5, and 5, which is 1. The least common multiple for the x is x^3, because it is the smallest exponent. The smallest multiple for y is 0, because the last factor doesn't even have y. For z, it is z^2. So your answer is 1x^3z^2, or just x^3,z^2.

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Two students in the same Spanish class, Perry and Dakota, plan to get together after school
shtirl [24]

Answer:

Dakota=20 perry=25 together= 45

Step-by-step explanation:

First step, remember to keep 5

second step, if they are find keep multiplying until they both meet the same number which is 20, but they both have 20. But Perry will have 25 since he started a day before

3 0
3 years ago
Four speed skaters, Marco, Naim, Oliver, and Pedro, compete in a relay race where they all agree that Naim will be the last
allochka39001 [22]

Answer:

A = {MOPN, MPON, PMON, POMN}

Step-by-step explanation:

Everyone has already agreed that Naim would be the last skater, so we have to make sure that the result has 'N' in each last place. As we can see, they all have this.

Now, we also have to make sure Oliver <u>not</u> first, because although they're trying to decide, the problem asks for the <u>complement</u> in which "Oliver is the first skater in the race."

A complement is all the values that are NOT in the set, so it cannot be A = {OPMN, OMPN) or A = {MOPN,MPON, OPMN, POMN), because they both have at least one case where 'O' is first.

A complement is ALL other values of the set, so it cannot be A = {MOPN, PMON}, because that set only shows two possible values.

Therefore, A = {MOPN, MPON, PMON, POMN} is your answer.

5 0
2 years ago
Read 2 more answers
Please find question in photo below. I’m revising for a test I have in a few days, and I can’t figure this out. Please help!
Temka [501]

\large{\rm{\underline{\underline{Answer:}}}}

a) <u>n² + 6 </u>

~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.

  • If n = 1, first term = 1² + 6 = 7
  • n = 2, second term = 10
  • n = 3, third temm = 15
  • n = 4, fourth term = 22
  • n = 10, tenth term = 106

b) <u>3n²</u>

  • If n = 1, first term = 3
  • n = 2, second term = 12
  • n = 3, third term = 27
  • n = 4, fourth term = 48
  • n = 10, tenth term = 300
3 0
2 years ago
F(x)=2x+1/x-1 then f^-1(1)​
olasank [31]

Answer:

  • f⁻¹(x) = (x + 1) / (x - 2)
  • f⁻¹(1 ) = - 2

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = (2x + 1) / (x - 1)

<u>Find its inverse, substitute x with y and f(x) with x, solve for y:</u>

  • x = (2y + 1) / (y - 1)
  • x(y - 1) = 2y + 1
  • xy - x = 2y + 1
  • xy - 2y = x + 1
  • y(x - 2) = x + 1
  • y = (x + 1) / (x - 2)

<u>Substitute y with f⁻¹(x):</u>

  • f⁻¹(x) = (x + 1) / (x - 2)

<u>Find  f⁻¹(1 ):</u>

  • f⁻¹(1 ) = ( 1 + 1) / (1 - 2) = 2 / - 1 = - 2
6 0
2 years ago
........................
Ulleksa [173]

Answer:

...................... have no end

Step-by-step explanation:

Hope it will help

<h2><em>N</em><em>o</em><em>w</em><em> </em><em>,</em><em> </em><em>ca</em><em>n i</em><em> </em><em>g</em><em>e</em><em>t</em><em> </em><em>brainlists</em><em> </em><em>p</em><em>l</em><em>e</em><em>a</em><em>s</em><em>e</em></h2>
7 0
2 years ago
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