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3 years ago

What is the least common multiple. Thanks.

Mathematics

1 answer:

o-na [289]3 years ago

6 0

Before we start, find the LCM of 9, 5, and 5, which is 1. The least common multiple for the x is x^3, because it is the smallest exponent. The smallest multiple for y is 0, because the last factor doesn't even have y. For z, it is z^2. So your answer is 1x^3z^2, or just x^3,z^2.

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You are challenged to a lucky draw game. If you draw a face card (K, Q, J) from a standard deck of cards, you earn 10 points. If

Vilka [71]

To problem wants to compute the probability of the expected value that could be earn if you would draw again another card. So base on the fact that if draw a face card of K,Q,J from a standard deck correctly you will earn 10 point in just one draw, but loose 2 points if you another card, the probability that you would draw correct card in just one draw is 30.77%, so the possible value earn you have 2 points only

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3 years ago

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

andrew-mc [135]

Answer:

$z=\frac{7.4-7.6}{\frac{0.9}{\sqrt{130}}}=-2.534$

$z_{\alpha}=-2.054$

If the calculated value is less than the critical value we reject the null hypothesis.

P value

The p value for this test would be:

$p_v =P(Z$

Since the p value is lower than the significance level given we have enough evidence to reject the null hypothesis at the 25 of significance level given.

Step-by-step explanation:

Information given

$\bar X=7.6$ represent the sample mean

$\sigma=0.9$ represent the population deviation

$n=130$ sample size

$\mu_o =7.4$ represent the value that we want to check

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to check if the mean pressure is less then 7.6 pounds/square inch, the system of hypothesis are:

Null hypothesis: $\mu \geq 7.6$

Alternative hypothesis: $\mu < 7.6$

The statistic would be:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the values we got:

$z=\frac{7.4-7.6}{\frac{0.9}{\sqrt{130}}}=-2.534$

Critical value

we need to find a critical value who accumulates 0.02 of the area in the left of the normal standard distribution and we got:

$z_{\alpha}=-2.054$

If the calculated value is less than the critical value we reject the null hypothesis.

P value

The p value for this test would be:

$p_v =P(Z$

Since the p value is lower than the significance level given we have enough evidence to reject the null hypothesis at the 25 of significance level given.

3 0

3 years ago

Please help! I have a bunch more I will be posting as well , thank you! (:

notsponge [240]

15x + 30y = -10....reduce by dividing by 5
3x + 6y = -2...same as first equation...same line ..means infinite solutions

5 0

3 years ago

Help me pls and I need the answer fast

Igoryamba

Gosh idk btw nice profile pic i love potatos there tasty lollllll

8 0

3 years ago

Find the equation is standard form, of the line passing through he points (2,-3) and (4,2)

Simora [160]

The point slope formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(2,\ -3)\to x_1=2,\ y_1=-3\\(4,\ 2)\to x_2=4,\ y_2=2$

Substitute:

$m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}=2.5\\\\y-(-3)=2.5(x-2)\\\\y+3=2.5x-5\ \ \ \ |+5\\\\y+8=2.5x\ \ \ \ \ \ |-y\\\\2.5x-y=8\ \ \ \ \ |\cdot2\\\\\boxed{5x-2y=16}$

5 0

3 years ago