y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
<h2>PLEASE MARK BRAINLIEST!!</h2>
Yes
Answer: Its in the pic below
Step-by-step explanation: Hope this helps have a brilliant day- Lily ^_^
Answer:
3x+3=2x
Step-by-step explanation:
The complete pattern is: 512, 256, 128, 64, 32, 16, 8, ( and extended ) 4, 2, 1!
I do this pattern in my head literally all the time!
