3/x=5/y multiply both sides by y
3y/x=5 divide both sides by 3
y/x=5/3
Please find attached photograph for your answer.
Answer:
The maximum number of quarters that he could have is 13
Step-by-step explanation:
Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then
→ x + 10 >= 20
→ x >= 10 (1)
His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.
→ (x * 25) + (10 * 10) <= (4.25 * 100)
→ 25x + 100 <= 425
→ 25x <= 325
→ x <= 13 (2)
If we combine the equation 1 and 2:
10 <= x <= 13
The maximum value of x is 13
Answer:
y= 3x+5
Step-by-step explanation:
start with the linear equation formula
y= mx+b
indentify what you already have.
x= -1 and y= 2 and m(slope)= 3
We are solving for b, so plug in what you have.
2= 3(-1)+b
Simplify.
2= -3+b
Add 3 on both sides.
5= b
Rewrite your equation with the x and y values.
y= 3x+5
