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NARA [144]
3 years ago
10

A parking garage charges $5.50 to park for 4 hours and $7.75 to park for 7 hours. If the cost is a linear function of the number

of hours parked, what is the cost to park for 3 hours?
Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

see bottom

Step-by-step explanation:

y=mx+b

m=slope

b=yint

two points

cost=y

(4,5.5) and (7,7.75)

slope=(y2-y1)/(x2-x1)

slope=(7.75-5.5)/(7-4)=2.25/3=0.75

y=0.75x+b

find b

(4,5.5)

x=4

y=5.5

5.5=0.75(4)+b

5.5=3+b

minus 3 fromboth sides

2.5=b

y=0.75x+2.5

3 hours

y=0.75(3)+2.5

y=2.25+2.5

y=4.75

answer is D

Veseljchak [2.6K]3 years ago
5 0
Given:
hours     parking charge
4                 5.50
7                 7.75

7 - 4 = 3 hours
7.75 - 5.50 = 2.25

2.25 / 3 = 0.75

0.75 is the change in amount for every hour spent. It is the variable unit rate

4 hours is 5.50.

Cost of parking for 3 hours is: 5.50 - 0.75 = 4.75

0.75 x 4 hours = 3 
5.50 - 3 = 2.5 fixed charge.

total parking charge:  y = 2.50 + 0.75x
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A city has a population of 370,000 people. Suppose that each year the
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Step-by-step explanation:

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383,875 + 14,395 = 385,370

(end of second year)

3.75% of 385,370 is 14451.375, rounding it down to 14451

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(end of third year)

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399,821 + 14,933 = 414,754

(end of fourth year)

3.75% of 414,754 is 15553.275, but I'm rounding it down to 15,553

414,754 + 15,553 = 430,307

(end of fifth year)

3.75% of 430,307 is 16136.512499999999, but I'm rounding it down to 16,136

430,307 + 16,136 = 446,443

(end of sixth year)

3.75% of 446,443 is 16741.6125, but I'm rounding it up to 16,742

446,443 + 16,742 = 463,185

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