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NARA [144]
3 years ago
10

A parking garage charges $5.50 to park for 4 hours and $7.75 to park for 7 hours. If the cost is a linear function of the number

of hours parked, what is the cost to park for 3 hours?
Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

see bottom

Step-by-step explanation:

y=mx+b

m=slope

b=yint

two points

cost=y

(4,5.5) and (7,7.75)

slope=(y2-y1)/(x2-x1)

slope=(7.75-5.5)/(7-4)=2.25/3=0.75

y=0.75x+b

find b

(4,5.5)

x=4

y=5.5

5.5=0.75(4)+b

5.5=3+b

minus 3 fromboth sides

2.5=b

y=0.75x+2.5

3 hours

y=0.75(3)+2.5

y=2.25+2.5

y=4.75

answer is D

Veseljchak [2.6K]3 years ago
5 0
Given:
hours     parking charge
4                 5.50
7                 7.75

7 - 4 = 3 hours
7.75 - 5.50 = 2.25

2.25 / 3 = 0.75

0.75 is the change in amount for every hour spent. It is the variable unit rate

4 hours is 5.50.

Cost of parking for 3 hours is: 5.50 - 0.75 = 4.75

0.75 x 4 hours = 3 
5.50 - 3 = 2.5 fixed charge.

total parking charge:  y = 2.50 + 0.75x
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dmitriy555 [2]

Answer:

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Third option is correct.

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1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

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m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

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170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
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