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Tanya [424]
3 years ago
6

How many solutions exist for this equation 12x + 1 = 3(4x + 1) – 2

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Answer:

Infinitely many

Step-by-step explanation:

12x+1=3(4x+1)-2

12x+1=12x+1

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Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
2 years ago
-x-6=3<br> How do u do this
Hatshy [7]

Answer:

x= -9......................

3 0
3 years ago
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The Richards family bought some new camping gear at REI that totaled $318.50. If they receive a 30% discount, what is their tota
Alexeev081 [22]
318.50 x .30 = 95.55 discount.
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Express x^2y^2+x^2+y^2+1
Hitman42 [59]

Answer:

( y^2 +1) ( x^2+1)

Step-by-step explanation:

Step 1 ) Factor out x^2 from the expression

x^2 (y^2+1)+y^2+1

Step 2) Factor out y^2 from the expression

(y^2+1) (x^2+1)

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