Answer:
(I attach your complete question in the picture below)
The apparent frequency would be
f' = 493.26 Hz
Step-by-step explanation:
This a Doppler's effect problem. This effects produces a slight change in the frequency of a traveling wave, due to the effect of the velocity of the receiver (observer).
The formula used to describe the change, as both vehicles are moving away of each other:
f' = [ (Vwave + Vobserver) / (Vwave + Vsource ) ]*f
Where
Vwave = 340 m/s ( speed of sound)
Vobserver = 18.6 m/s (observer = car)
Vsource = 23.5 m/s (speed of the ambulance = source)
f = 500 Hz (frequency of the sound)
We just need to substitute in the equation
f' = [(340+ 18.6) / (340+ 23.5)] * 500 Hz
f' = [0.9865] * 500 Hz = 493.26 Hz
f' = 493.26 Hz
Since I can't draw a model the answer is equal because if you reduce 6/8 the answer is 3/4
Answer:
No solution
Step-by-step explanation:
6X - 3Y = -9--------------(1)
- 2 X +Y= 5---------------(2)
from equation two,
Y = 5+2X------------------(3)
substitute equation (3) into equation (1)
6X-3(5+2X)= -9
opening bracket
6X-15-6X= -9
6X- 6X = -9+15
0 = 6
<h2>therefore the answer is no solution</h2>