I need help with surface area for a pyrimid please

Mathematics

4 answers:

IrinaVladis [17]3 years ago

6 0

Okay do find the area of a triangle and then add it to the area of the rectangles

exis [7]3 years ago

6 0

SA = Base Area • 2 + base perimeter • distance

SA = 1/2(12•8)+(12+10+10)•10
1/2(96)+(32•10)
48+320
SA= 368

Svetlanka [38]3 years ago

5 0

SA = Base Area • 2 + base perimeter • distance

SA = 1/2(12•8)+(12+10+10)•10
1/2(96)+(32•10)
48+320
SA= 368

kifflom [539]3 years ago

5 0

SA = Base Area • 2 + base perimeter • distance

SA = 1/2(12•8)+(12+10+10)•10
1/2(96)+(32•10)
48+320
SA= 368

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The line y = 2x - 16 is a tangent to the curve y = ax³ + bx at the point where x = 2. Find the value of a and of b.

finlep [7]

I might not be right but a is 2 and b is 16

Step-by-step explanation:

7 0

3 years ago

Find the directional derivative of the function at the given point in the direction of the vector v. h(r, s, t) = ln(3r + 6s + 9

vodka [1.7K]

Answer:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})$

Step-by-step explanation:

First, let’s check to see if the direction vector is a unit vector:

$||v||=\sqrt{(14)^{2} +(42)^{2} +(21)^{2} } =\sqrt{2401} =49$

It’s not a unit vector. therefore let's divide the vector by its magnitude in order to convert it into a unit vector:

$\overrightarrow{\rm v}=(\frac{14}{49}\overrightarrow{\rm i})+(\frac{42}{49}\overrightarrow{\rm j})+(\frac{21}{49}\overrightarrow{\rm k})= (\frac{2}{7}\overrightarrow{\rm i})+(\frac{6}{7}\overrightarrow{\rm j})+(\frac{3}{7}\overrightarrow{\rm k})$

Now, the directional derivative is given by:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=\frac{\partial h(r,s,t)}{\partial r}\overrightarrow{\rm i} + \frac{\partial h(r,s,t)}{\partial s}\overrightarrow{\rm j} + \frac{\partial h(r,s,t)}{\partial t}\overrightarrow{\rm k}$